How do i show 00 in python?

How do I display a leading zero for all numbers with less than two digits?

1    →  01
10   →  10
100  →  100

Mateen Ulhaq

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asked Sep 25, 2008 at 18:06

ashchristopherashchristopher

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0

In Python 2 (and Python 3) you can do:

number = 1
print("%02d" % (number,))

Basically % is like printf or sprintf (see docs).

For Python 3.+, the same behavior can also be achieved with format:

number = 1
print("{:02d}".format(number))

For Python 3.6+ the same behavior can be achieved with f-strings:

number = 1
print(f"{number:02d}")

Flimm

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answered Sep 25, 2008 at 18:08

9

You can use str.zfill:

print(str(1).zfill(2))
print(str(10).zfill(2))
print(str(100).zfill(2))

prints:

01
10
100

Neuron

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answered Jul 30, 2010 at 11:58

DatageekDatageek

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In Python 2.6+ and 3.0+, you would use the format() string method:

for i in (1, 10, 100):
    print('{num:02d}'.format(num=i))

or using the built-in (for a single number):

print(format(i, '02d'))

See the PEP-3101 documentation for the new formatting functions.

phoenix

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answered Sep 25, 2008 at 18:43

BerBer

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2

print('{:02}'.format(1))
print('{:02}'.format(10))
print('{:02}'.format(100))

prints:

01
10
100

Neuron

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answered Nov 13, 2013 at 19:30

KresimirKresimir

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2

In Python >= 3.6, you can do this succinctly with the new f-strings that were introduced by using:

f'{val:02}'

which prints the variable with name val with a fill value of 0 and a width of 2.

For your specific example you can do this nicely in a loop:

a, b, c = 1, 10, 100
for val in [a, b, c]:
    print(f'{val:02}')

which prints:

01 
10
100

For more information on f-strings, take a look at PEP 498 where they were introduced.

Neuron

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answered Nov 28, 2017 at 14:52

Or this:

print '{0:02d}'.format(1)

answered Nov 10, 2010 at 10:03

ajdajd

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The Pythonic way to do this:

str(number).rjust(string_width, fill_char)

This way, the original string is returned unchanged if its length is greater than string_width. Example:

a = [1, 10, 100]
for num in a:
    print str(num).rjust(2, '0')

Results:

01
10
100

Neuron

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answered Apr 27, 2012 at 22:02

ZuLuZuLu

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0

Or another solution.

"{:0>2}".format(number)

Kenly

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answered Nov 22, 2015 at 21:01

WinterChillyWinterChilly

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1

You can do this with f strings.

import numpy as np

print(f'{np.random.choice([1, 124, 13566]):0>8}')

This will print constant length of 8, and pad the rest with leading 0.

00000001
00000124
00013566

answered Mar 11, 2020 at 18:50

Nicolas GervaisNicolas Gervais

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This is how I do it:

str(1).zfill(len(str(total)))

Basically zfill takes the number of leading zeros you want to add, so it's easy to take the biggest number, turn it into a string and get the length, like this:

Python 3.6.5 (default, May 11 2018, 04:00:52) 
[GCC 8.1.0] on linux
Type "help", "copyright", "credits" or "license" for more information.
>>> total = 100
>>> print(str(1).zfill(len(str(total))))
001
>>> total = 1000
>>> print(str(1).zfill(len(str(total))))
0001
>>> total = 10000
>>> print(str(1).zfill(len(str(total))))
00001
>>> 

answered Jun 21, 2018 at 0:43

RobertoRoberto

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1

width = 5
num = 3
formatted = (width - len(str(num))) * "0" + str(num)
print formatted

answered Nov 15, 2013 at 16:33

nvdnvd

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Use:

'00'[len(str(i)):] + str(i)

Or with the math module:

import math
'00'[math.ceil(math.log(i, 10)):] + str(i)

answered Apr 20, 2018 at 13:21

All of these create the string "01":

>python -m timeit "'{:02d}'.format(1)"
1000000 loops, best of 5: 357 nsec per loop

>python -m timeit "'{0:0{1}d}'.format(1,2)"
500000 loops, best of 5: 607 nsec per loop

>python -m timeit "f'{1:02d}'"
1000000 loops, best of 5: 281 nsec per loop

>python -m timeit "f'{1:0{2}d}'"
500000 loops, best of 5: 423 nsec per loop

>python -m timeit "str(1).zfill(2)"
1000000 loops, best of 5: 271 nsec per loop

>python
Python 3.8.1 (tags/v3.8.1:1b293b6, Dec 18 2019, 23:11:46) [MSC v.1916 64 bit (AMD64)] on win32

answered Mar 9, 2021 at 18:51

handlehandle

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This would be the Python way, although I would include the parameter for clarity - "{0:0>2}".format(number), if someone will wants nLeadingZeros they should note they can also do:"{0:0>{1}}".format(number, nLeadingZeros + 1)

answered Oct 2, 2021 at 11:23

You could also do:

'{:0>2}'.format(1)

which will return a string.

answered May 16 at 19:04

If dealing with numbers that are either one or two digits:

'0'+str(number)[-2:] or '0{0}'.format(number)[-2:]

answered Feb 19, 2016 at 4:20

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