Complete Study Material based on Class 12th Syllabus, 10000+ Question Bank, Unlimited Chapter-Wise and Subject-Wise Mock Tests, Study Improvement Plan. Nội dung chính
₹ 7999/- ₹ 4999/-
Buy NowComplete Study Material based on Class 12th Syllabus, 10000+ Question Bank, Unlimited Chapter-Wise and Subject-Wise Mock Tests, Study Improvement Plan.
₹ 7999/- ₹ 4999/-
Buy Now- AI Coach Study Modules, - Unlimited Mock Tests, - Expert Mentorship, - Study Improvement Plan.
₹ 9999/- ₹ 8499/-
Buy Now- AI Coach Study Modules, - Unlimited Mock Tests, - Expert Mentorship, - Study Improvement Plan.
₹ 13999/- ₹ 12499/-
Buy Now- AI Coach Study Modules, - Unlimited Mock Tests, - Expert Mentorship, - Study Improvement Plan.
₹ 9999/- ₹ 8499/-
Buy NowNội dung chính
- How many 4 digits numbers can be formed using digits 1,2 3 5 7 9 repetition not allowed?
- How many 4 digit numbers can be formed with repetition?
- How many 4 digit numbers can be formed using the digits 1 3 4 5 7 9 sum of digits is not allowed?
- How many 4 digits numbers greater than 7000 can be formed out of the digits?
How many 4-digit numbers greater than 7000 can be formed by using the digits 3, 5, 7, 8, 9, if repetition is not allowed?
Solution not provided.
Ans. 72
178 Views
A coin is tossed 3 times and the outcomes are recorded. How many possible outcomes are there?
Event 1: A coin is tossed and the outcomes recorded.
Number of outcomes
m = 2Event 2: The coin is tossed again and the outcomes recorded.
Number of outcomes
n = 2Event 3: The coin is tossed third time and the outcomes recorded.
Number of outcomes
p = 2∴ By fundamental principle of counting, the total number of outcomes recorded =
548 Views
How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that repetition of the digits is not allowed.
Number of ways in which place [x] can be filled = 5
m = 5
Number of ways in which place [y] can be filled = 4 [∵ Repetition is not allowed]
n = 4
Number of ways in which place [z] can be filled = 3 [∵ Repetition is not allowed]
p = 3
∴ By fundamental principle of counting, the total number of 3 digit numbers formed = m x n x p = 5 x 4 x 3 = 60.
526 Views
How many 3-digit odd numbers can be formed from the digits 1,2,3,4,5,6 if:
[a] the digits can be repeated [b] the digits cannot be repeated?
[a] Number of digits available = 6
Number of places [[x], [y] and [z]] for them = 3
Repetition is allowed and the 3-digit numbers formed are odd
Number of ways in which box [x] can be filled = 3 [by 1, 3 or 5 as the numbers formed are to be odd]
m = 3Number of ways of filling box [y] = 6 [∴ Repetition is allowed] n = 6
Number of ways of filling box [z] = 6 [∵ Repetition is allowed]
p = 6∴ Total number of 3-digit odd numbers formed
= m x n x p = 3 x 6 x 6 = 108
[b] Number of ways of filling box [x] = 3 [only odd numbers are to be in this box ]
m = 3Number of ways of filling box [y] = 5 [∵ Repetition is not allowed]
n = 5Number of ways of filling box [z] = 4 [∵ Repetition is not allowed]
p = 4∴ Total number of 3-digit odd numbers formed
= m x n x p = 3 x 5 x 4 = 60.
231 Views
Given 5 flags of different colours, how many different signals can be generated if each signal requires use of 2 flags, one below the other?
Number of ways of finding a flag for place 1 = 5
m = 5Number of remaining flags = 4
Number of ways of finding a flag for place 2 to complete the signal = 4
n = 4∴ By fundamental principle of counting, the number of signals generated =
991 Views
How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that repetition of the digits is allowed.
Number of digits available = 5
Number of places for the digits = 3.
Number of ways in which place [x] can be filled = 5
m = 5
Number of ways in which place [y] can be filled = 5 [∵ Repetition is allowed]
n = 5
Number of ways in which place [z] can be filled = 5 [∵ Repetition is allowed]
p = 5
∴ By fundamental principle of counting, the number of 3-digit numbers formed. = m x n x p = 5 x 5 x 5 = 125
458 Views
How many 4 digits numbers can be formed using digits 1,2 3 5 7 9 repetition not allowed?
Number of 4-digit
numbers `=[4xx3xx2xx1]=24. `
Hence, the number of required numbers `=[4+12+24+24]=64. ` Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.
How many 4 digit numbers can be formed with repetition?
There is 4 possible ways to fill hundredth place as digits cannot be repeated. There is 3 possible ways to fill the first place of four digit number. ∴ 60 four-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9.
How many 4 digit numbers can be formed using the digits 1 3 4 5 7 9 sum of digits is not allowed?
1 Answer. We know that the number of 4 digited numbers that can be formed using the digits 1, 3, 5, 7, 9 is 5P4 = 120.
How many 4 digits numbers greater than 7000 can be formed out of the digits?
Since you didn't state that digits cannot be repeated, the answer is 4^4 = 256 different numbers.
How many four digit numbers can be formed with the digits 3 5 7 8 9 which are Greaterthan 8000 if repetition of digits is not allowed?
1 Answer. The required numbers are greater than 8000. Therefore, the thousand's place can be filled with 2 digits: 8 or 9. Thus total number of possible outcomes is 2C1 × 4C1 × 3C1 × 2C1 = 2 × 4 × 3 × 2 = 48.
How many 2 digit numbers can be formed with the digits 3 5 6 7 8 if none of the digits is repeated in any of the numbers formed?
∴ Required number of numbers = [1 x 5 x 4] = 20. Was this answer helpful?
How many 8 digit numbers can be formed with the digits 3/5 and 7?
6561 eight-digit numbers can be made from the digits 3, 5 and 7.
How many 3 digit numbers can be formed using the digits 1 3 5 7 9 where we are not allowed to repeat the digits?
Therefore, a total of 100 3 digit numbers can be formed using the digits 0, 1, 3, 5, 7 when repetition is allowed.