How many words, with or without meaning, each of 3 vowels and 2 consonants DAUGHTER
|
The word is 'INVOLUTE'  (ii) Select two consonants out of 4. (iii) Arrange the five letters (3 vowels + 2 consonants) to form words. Number of permutations = 5! (iv) Apply fundamental principle of counting: Show Number of words formed = = = 4 x 6 x 120 = 2880 216 Views Permutations and CombinationsHope you found this question and answer to be good. Find many more questions on Permutations and Combinations with answers for your assignments and practice. MathematicsBrowse through more topics from Mathematics for questions and snapshot. My solution: In the word INVOLUTE, there are $4$ vowels, namely, I,O,E,U and $4$ consonants, namely, N, V, L and T. The number of ways of selecting $3$ vowels out of $4 = C(4,3) = 4$. The number of ways of selecting $2$ consonants out of $4 = C(4,2) = 6$. Therefore, the number of combinations of $3$ vowels and $2$ consonants is $4+6=10$. Now, each of these $10$ combinations has $5$ letters which can be arranged among themselves in $5!$ ways. Therefore, the required number of different words is $10\times5! = 1200$. But the answer is $2880$. What am I doing wrong? Please explain. How many words with or without meaning each of 3 vowels and 2 consonants can?Required number of ways =2880.
How many words can be formed with 3 consonants and 2 vowels?So now we have 2 vowels and 3 consonants, which means that we have 5 letters in total. Final Answer: Total no. of words formed by using 2 vowels and 3 consonants taken from 4 vowels and 5 constants in equal to 7200.
How many words with or without meaning can be formed using daughter?Therefore, 30 words can be formed from the letters of the word DAUGHTER each containing 2 vowels and 3 consonants.
How many vowels are there in daughter?Given word 'DAUGHTER' has 8 letters in which 3 are vowels and 5 are consonants. A, U, E are vowels and D, G, H, T, R are consonants.
|
