Hướng dẫn how do you count the occurrences of a particular element in the string in python? - làm thế nào để bạn đếm số lần xuất hiện của một phần tử cụ thể trong chuỗi trong python?

Trong hướng dẫn này, chúng tôi sẽ tìm hiểu về phương thức Count [] chuỗi Python với sự trợ giúp của các ví dụ.

Phương thức

string.count[substring, start=..., end=...]

Thí dụ

message = 'python is popular programming language'

# number of occurrence of 'p'
print['Number of occurrence of p:', message.count['p']]

# Output: Number of occurrence of p: 4

Cú pháp của số lượng chuỗi

Phương pháp cú pháp của phương pháp

string.count[substring, start=..., end=...]

string.count[substring, start=..., end=...]

Count [] tham số

Phương thức

string.count[substring, start=..., end=...]

• Chất nền - chuỗi có số lượng sẽ được tìm thấy. - string whose count is to be found.
• Bắt đầu [Tùy chọn] - Chỉ mục bắt đầu trong chuỗi nơi tìm kiếm bắt đầu. - starting index within the string where search starts.
• Kết thúc [Tùy chọn] - Chỉ mục kết thúc trong chuỗi nơi tìm kiếm kết thúc. - ending index within the string where search ends.

Lưu ý: Chỉ mục trong Python bắt đầu từ 0, không phải 1. Index in Python starts from 0, not 1.

Đếm [] Giá trị trả về

Phương thức

string.count[substring, start=..., end=...]

Ví dụ 1: Số lượng xuất hiện của một chuỗi con đã cho

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

Đầu ra

The count is: 2

Ví dụ 2: Số lần xuất hiện của một chuỗi con nhất định bằng cách sử dụng bắt đầu và kết thúc

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

Đầu ra

The count is: 1

Ví dụ 2: Số lần xuất hiện của một chuỗi con nhất định bằng cách sử dụng bắt đầu và kết thúc

Ở đây, việc đếm bắt đầu sau khi

string.count[substring, start=..., end=...]

string.count[substring, start=..., end=...]

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

& nbsp; Phương pháp #5: Sử dụng

string.count[substring, start=..., end=...]

Biểu thức thường xuyên có thể giúp chúng tôi đạt được nhiều nhiệm vụ mã hóa liên quan đến chuỗi. Họ cũng có thể tạo điều kiện cho chúng tôi đạt được nhiệm vụ tìm kiếm sự xuất hiện của phần tử trong chuỗi.

string.count[substring, start=..., end=...]

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

The count is: 1

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

The count is: 1

The count is: 2

The count is: 1

________ 62 ________ 40 & nbsp;

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

Count of e in GeeksforGeeks is : 4

Phương pháp số 3: Sử dụng

Count of e in GeeksforGeeks is : 4

The count is: 2

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

________ 45 ________ 40 & nbsp;

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

Đầu ra:

Count of e in GeeksforGeeks is : 4

Phương pháp số 2: Sử dụng

string.count[substring, start=..., end=...]

string.count[substring, start=..., end=...]

Sử dụng

string.count[substring, start=..., end=...]

string.count[substring, start=..., end=...]

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

The count is: 1

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

The count is: 1

The count is: 2

The count is: 1

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

________ 45 ________ 40 & nbsp;

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

  



# print count
print["The count is:", count]

Đầu ra:

Count of e in GeeksforGeeks is : 4

Phương pháp số 2: Sử dụng

string.count[substring, start=..., end=...]

Count of e in GeeksforGeeks is : 4

Sử dụng

string.count[substring, start=..., end=...]

Count of e in GeeksforGeeks is : 4

Count of e in GeeksforGeeks is : 4

Count of e in GeeksforGeeks is : 4

Count of e in GeeksforGeeks is : 4

string.count[substring, start=..., end=...]

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

Count of e in GeeksforGeeks is : 4

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

________ 80 ________ 40 & nbsp;

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

Count of e in GeeksforGeeks is : 4

The count is: 2

Count of e in GeeksforGeeks is : 4

Đầu ra:

Count of e in GeeksforGeeks is : 4

Phương pháp số 4: Sử dụng Lambda +

Count of e in GeeksforGeeks is : 4

Count of e in GeeksforGeeks is : 4

Count of e in GeeksforGeeks is : 4

Count of e in GeeksforGeeks is : 4

Các chức năng của Lambda, cùng với

Count of e in GeeksforGeeks is : 4

string.count[substring, start=..., end=...]

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

Count of e in GeeksforGeeks is : 4

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

________ 80 ________ 40 & nbsp;

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

Count of e in GeeksforGeeks is : 4

The count is: 2

Count of e in GeeksforGeeks is : 4

Đầu ra:

Count of e in GeeksforGeeks is : 4

Phương pháp số 4: Sử dụng Lambda +

Count of e in GeeksforGeeks is : 4

Count of e in GeeksforGeeks is : 4

string.count[substring, start=..., end=...]

Các chức năng của Lambda, cùng với

Count of e in GeeksforGeeks is : 4

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

string.count[substring, start=..., end=...]

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "is"

count = string.count[substring]

# print count
print["The count is:", count]

________ 45 ________ 40 & nbsp;

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

________ 80 ________ 40 & nbsp;

# define string
string = "Python is awesome, isn't it?"
substring = "i"

# count after first 'i' and before the last 'i'
count = string.count[substring, 8, 25]

# print count
print["The count is:", count]

Count of e in GeeksforGeeks is : 4

The count is: 2

Count of e in GeeksforGeeks is : 4

Đầu ra:

Count of e in GeeksforGeeks is : 4

Làm thế nào để bạn tìm thấy số lần xuất hiện của một chuỗi cụ thể trong Python?

Làm thế nào để bạn đếm các sự xuất hiện của một phần tử cụ thể trong một chuỗi?

Làm thế nào để bạn đếm các sự xuất hiện của mỗi từ trong một chuỗi trong Python?

Làm thế nào để bạn đếm sự xuất hiện của mỗi ký tự trong một chuỗi?