Hướng dẫn python date yesterday

I need to find "yesterday's" date in this format MMDDYY in Python.

So for instance, today's date would be represented like this: 111009

I can easily do this for today but I have trouble doing it automatically for "yesterday".

the

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asked Nov 11, 2009 at 0:01

Use datetime.timedelta[]

>>> from datetime import date, timedelta
>>> yesterday = date.today[] - timedelta[days=1]
>>> yesterday.strftime['%m%d%y']
'110909'

answered Nov 11, 2009 at 0:03

Jarret HardieJarret Hardie

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2

from datetime import datetime, timedelta

yesterday = datetime.now[] - timedelta[days=1]
yesterday.strftime['%m%d%y']

answered Nov 11, 2009 at 0:04

Nadia AlramliNadia Alramli

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0

This should do what you want:

import datetime
yesterday = datetime.datetime.now[] - datetime.timedelta[days = 1]
print yesterday.strftime["%m%d%y"]

answered Nov 11, 2009 at 0:03

StefStef

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all answers are correct, but I want to mention that time delta accepts negative arguments.

>>> from datetime import date, timedelta
>>> yesterday = date.today[] + timedelta[days=-1]
>>> print[yesterday.strftime['%m%d%y']] #for python2 remove parentheses 

answered Sep 18, 2017 at 7:21

Iman MirzadehIman Mirzadeh

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Could I just make this somewhat more international and format the date according to the international standard and not in the weird month-day-year, that is common in the US?

from datetime import datetime, timedelta

yesterday = datetime.now[] - timedelta[days=1]
yesterday.strftime['%Y-%m-%d']

answered Dec 4, 2018 at 12:08

2

To expand on the answer given by Chris

if you want to store the date in a variable in a specific format, this is the shortest and most effective way as far as I know

>>> from datetime import date, timedelta                   
>>> yesterday = [date.today[] - timedelta[days=1]].strftime['%m%d%y']
>>> yesterday
'020817'

If you want it as an integer [which can be useful]

>>> yesterday = int[[date.today[] - timedelta[days=1]].strftime['%m%d%y']]
>>> yesterday
20817

answered Feb 9, 2017 at 19:18