Hướng dẫn split without space python

I take a string of integers as input and there are no spaces or any kind of separator:

12345

Now I want this string to converted into a list of individual digits

[1,2,3,4,5]

I've tried both

numlist = map[int,input[].split[""]]

and

numlist = map[int,input[].split[""]]

Both of them give me Empty Separator error. Is there any other function to perform this task?

asked Apr 2, 2015 at 9:18

0

You don't need to use split here:

>>> a = "12345"    
>>> map[int, a]
[1, 2, 3, 4, 5]

Strings are Iterable too

For python 3x:

list[map[int, a]]

answered Apr 2, 2015 at 9:20

HackaholicHackaholic

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1

Use list_comprehension.

>>> s = "12345"
>>> [int[i] for i in s]
[1, 2, 3, 4, 5]

answered Apr 2, 2015 at 9:20

Avinash RajAvinash Raj

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1

The answers are brilliant. Here is an approach using regex

>>> import re
>>> s = '12345'
>>> re.findall[r'\d',s]
['1', '2', '3', '4', '5']

Ref - Docs on Regex

Why use regex for everything?

answered Apr 2, 2015 at 9:23

Bhargav RaoBhargav Rao

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You also can use

>>> range[1,6]
[1, 2, 3, 4, 5]

answered Apr 2, 2015 at 9:21

Ishikawa YoshiIshikawa Yoshi

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4

How to split a string without spaces in Python #

To split a string without spaces:

1. Use the list[] class to split a string into a list of strings.
2. Use a list comprehension to split a string into a list of integers.

Copied!
my_str = 'abcde'

# ✅ split string without spaces into list of characters
list_of_strings = list[my_str]
print[list_of_strings]  # 👉️ ['a', 'b', 'c', 'd', 'e']
# ---------------

# ✅ split string without spaces into list of integers
my_str_2 = '123456'

list_of_ints = [int[x] for x in my_str_2]
print[list_of_ints]  # 👉️ [1, 2, 3, 4, 5, 6]

The first example uses the list[] class to split a string without spaces.

The list class takes an iterable and returns a list object.

When passed a string, the list class splits the string into a list of characters.

If you need to split a string without spaces into a list of integers, use a list comprehension.

Copied!
my_str_2 = '123456'

list_of_ints = [int[x] for x in my_str_2]
print[list_of_ints]  # 👉️ [1, 2, 3, 4, 5, 6]

We iterate directly over the string and on each iteration, we convert the digit that is wrapped in a string to an integer.

List comprehensions are used to perform some operation for every element, or select a subset of elements that meet a condition.

An alternative approach is to use the map[] function.

Copied!
my_str_2 = '123456'

list_of_ints = list[map[int, my_str_2]]
print[list_of_ints]  # 👉️ [1, 2, 3, 4, 5, 6]

The map[] function takes a function and an iterable as arguments and calls the function with each item of the iterable.

We passed the int[] class for the function to map and passed it the string for the iterable.

Now the map[] function will pass each digit that is wrapped in a string to the int[] class.

Note that the map[] function returns a map object, so we have to use the list[] class to covert the map object to a list.