The zip function is useful here, used with a list comprehension.
[x + y for x, y in zip[first, second]]
If you have a list of lists [instead of just two lists]:
lists_of_lists = [[1, 2, 3], [4, 5, 6]]
[sum[x] for x in zip[*lists_of_lists]]
# -> [5, 7, 9]
answered Dec 27, 2012 at 7:12
8
From docs
import operator
list[map[operator.add, first,second]]
answered Dec 27, 2012 at 7:29
Thai TranThai Tran
9,6557 gold badges41 silver badges62 bronze badges
1
Default behavior in numpy.add [numpy.subtract, etc] is element-wise:
import numpy as np
np.add[first, second]
which outputs
array[[7,9,11,13,15]]
mirekphd
3,24025 silver badges44 bronze badges
answered Apr 28, 2014 at 19:57
user3582790user3582790
5694 silver badges2 bronze badges
7
Assuming both lists a and b have same length, you do not need zip, numpy or anything else.
Python 2.x and 3.x:
[a[i]+b[i] for i in range[len[a]]]
maro
4533 gold badges11 silver badges29 bronze badges
answered Jun 30, 2014 at 15:31
mathmath
8,22610 gold badges51 silver badges60 bronze badges
1
Try the following code:
first = [1, 2, 3, 4]
second = [2, 3, 4, 5]
third = map[sum, zip[first, second]]
kenorb
144k76 gold badges653 silver badges708 bronze badges
answered May 16, 2015 at 12:45
1
This extends itself to any number of lists:
[sum[sublist] for sublist in itertools.izip[*myListOfLists]]
In your case, myListOfLists would be [first, second]
answered Dec 27, 2012 at 7:20
inspectorG4dgetinspectorG4dget
106k25 gold badges137 silver badges234 bronze badges
2
The easy way and fast way to do this is:
three = [sum[i] for i in zip[first,second]] # [7,9,11,13,15]
Alternatively, you can use numpy sum:
from numpy import sum
three = sum[[first,second], axis=0] # array[[7,9,11,13,15]]
answered Mar 17, 2013 at 9:25
ThiruThiru
3,0737 gold badges34 silver badges49 bronze badges
1
one-liner solution
list[map[lambda x,y: x+y, a,b]]
answered Jul 25, 2019 at 7:36
ShadowmanShadowman
611 silver badge4 bronze badges
first = [1, 2, 3, 4, 5]
second = [6, 7, 8, 9, 10]
three = list[map[sum, first, second]]
print[three]
# Output
[7, 9, 11, 13, 15]
KetZoomer
2,4783 gold badges13 silver badges37 bronze badges
answered Jul 21, 2017 at 8:11
Anurag MisraAnurag Misra
1,41217 silver badges23 bronze badges
1
If you have an unknown number of lists of the same length, you can use the below function.
Here the *args accepts a variable number of list arguments [but only sums the same number of elements in each]. The * is used again to unpack the elements in each of the lists.
def sum_lists[*args]:
return list[map[sum, zip[*args]]]
a = [1,2,3]
b = [1,2,3]
sum_lists[a,b]
Output:
[2, 4, 6]
Or with 3 lists
sum_lists[[5,5,5,5,5], [10,10,10,10,10], [4,4,4,4,4]]
Output:
[19, 19, 19, 19, 19]
answered May 19, 2019 at 13:44
0
My answer is repeated with Thiru's that answered it in Mar 17 at 9:25.
It was simpler and quicker, here are his solutions:
The easy way and fast way to do this is:
three = [sum[i] for i in zip[first,second]] # [7,9,11,13,15]Alternatively, you can use numpy sum:
from numpy import sum three = sum[[first,second], axis=0] # array[[7,9,11,13,15]]
You need numpy!
numpy array could do some operation like vectors
import numpy as np
a = [1,2,3,4,5]
b = [6,7,8,9,10]
c = list[np.array[a] + np.array[b]]
print c
# [7, 9, 11, 13, 15]
answered Oct 22, 2013 at 9:58
PiecePiece
212 bronze badges
1
What if you have list with different length, then you can try something like this [using zip_longest]
from itertools import zip_longest # izip_longest for python2.x
l1 = [1, 2, 3]
l2 = [4, 5, 6, 7]
>>> list[map[sum, zip_longest[l1, l2, fillvalue=0]]]
[5, 7, 9, 7]
answered Apr 26, 2020 at 19:21
mohammed wazeemmohammed wazeem
1,2251 gold badge8 silver badges25 bronze badges
You can use zip[], which will "interleave" the two arrays together, and then map[], which will apply a function
to each element in an iterable:
>>> a = [1,2,3,4,5]
>>> b = [6,7,8,9,10]
>>> zip[a, b]
[[1, 6], [2, 7], [3, 8], [4, 9], [5, 10]]
>>> map[lambda x: x[0] + x[1], zip[a, b]]
[7, 9, 11, 13, 15]
answered Dec 27, 2012 at 7:12
cdhowiecdhowie
149k23 gold badges278 silver badges290 bronze badges
Here is another way to do it. We make use of the internal __add__ function of python:
class SumList[object]:
def __init__[self, this_list]:
self.mylist = this_list
def __add__[self, other]:
new_list = []
zipped_list = zip[self.mylist, other.mylist]
for item in zipped_list:
new_list.append[item[0] + item[1]]
return SumList[new_list]
def __repr__[self]:
return str[self.mylist]
list1 = SumList[[1,2,3,4,5]]
list2 = SumList[[10,20,30,40,50]]
sum_list1_list2 = list1 + list2
print[sum_list1_list2]
Output
[11, 22, 33, 44, 55]
TrakJohnson
1,6292 gold badges17 silver badges30 bronze badges
answered Sep 23, 2016 at 19:18
StrykerStryker
5,33254 silver badges64 bronze badges
If you want to add also the rest of the values in the lists you can use this [this is working in Python3.5]
def addVectors[v1, v2]:
sum = [x + y for x, y in zip[v1, v2]]
if not len[v1] >= len[v2]:
sum += v2[len[v1]:]
else:
sum += v1[len[v2]:]
return sum
#for testing
if __name__=='__main__':
a = [1, 2]
b = [1, 2, 3, 4]
print[a]
print[b]
print[addVectors[a,b]]
answered May 10, 2017 at 10:59
first = [1,2,3,4,5]
second = [6,7,8,9,10]
#one way
third = [x + y for x, y in zip[first, second]]
print["third" , third]
#otherway
fourth = []
for i,j in zip[first,second]:
global fourth
fourth.append[i + j]
print["fourth" , fourth ]
#third [7, 9, 11, 13, 15]
#fourth [7, 9, 11, 13, 15]
answered Jul 5, 2017 at 11:49
Here is another way to do it.It is working fine for me .
N=int[input[]]
num1 = list[map[int, input[].split[]]]
num2 = list[map[int, input[].split[]]]
sum=[]
for i in range[0,N]:
sum.append[num1[i]+num2[i]]
for element in sum:
print[element, end=" "]
print[""]
Agney
17k7 gold badges50 silver badges72 bronze badges
answered Sep 11, 2017 at 19:49
j = min[len[l1], len[l2]]
l3 = [l1[i]+l2[i] for i in range[j]]
Cris Luengo
51.1k7 gold badges59 silver badges113 bronze badges
answered Dec 27, 2017 at 5:06
1
If you consider your lists as numpy array, then you need to easily sum them:
import numpy as np
third = np.array[first] + np.array[second]
print third
[7, 9, 11, 13, 15]
answered Apr 25, 2019 at 10:32
RadvinRadvin
1434 silver badges10 bronze badges
Perhaps the simplest approach:
first = [1,2,3,4,5]
second = [6,7,8,9,10]
three=[]
for i in range[0,5]:
three.append[first[i]+second[i]]
print[three]
answered Jul 26, 2018 at 15:20
first = [1,2,3,4,5]
second = [6,7,8,9,10]
third=[]
for i,j in zip[first,second]:
t=i+j
third.append[t]
print["Third List=",third]
output -- Third List= [7, 9, 11, 13, 15]
answered Sep 13 at 7:51
New contributor
Sahil Rajput is a new contributor to this site. Take care in asking for clarification, commenting, and answering. Check out our Code of Conduct.
You can use this method but it will work only if both the list are of the same size:
first = [1, 2, 3, 4, 5]
second = [6, 7, 8, 9, 10]
third = []
a = len[first]
b = int[0]
while True:
x = first[b]
y = second[b]
ans = x + y
third.append[ans]
b = b + 1
if b == a:
break
print third
answered Dec 27, 2012 at 11:52
HelloUniHelloUni
4482 gold badges5 silver badges10 bronze badges