Php add 30 minutes to datetime

So what I need to do is add 30 minutes to the following

date("Ymdhis");

I tried this

+strtotime("+30 minutes");

however it does not seem to like it. I wondering what the correct why to do this is.

asked Mar 22, 2012 at 22:47

RussellHarrowerRussellHarrower

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1

Your method of using strtotime should work.

Output

2012/03/22 10:55:45
2012/03/22 11:25:45 // 30 minutes later

However your method of adding time probably isn't correct. The above will work to add 30 minutes to the current time. Suppose you want to add 30 minutes from a given time, $t, then use strtotime's second parameter, which is used as a base for the calculation of relative dates.

date("Y/m/d H:i:s", strtotime("+30 minutes", $t));

http://codepad.org/Z5yquF55

answered Mar 22, 2012 at 22:56

I tested this code but it doesn't work for me:

 $t = date();  
 date("Y/m/d h:i:s", strtotime("+30 minutes", $t));

Here's my solution

 //This is where you put the date, but I use the current date for this example
 $date = date("Y-m-d H:i:s");

 //Convert the variable date using strtotime and 30 minutes then format it again on the desired date format
 $add_min = date("Y-m-d H:i:s", strtotime($date . "+30 minutes"));
 echo  $date . "
"; //current date or whatever date you want to put in here
 echo  $add_min; //add 30 minutes

answered Mar 23, 2012 at 5:38

SuperNoobSuperNoob

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strtotime() accepts a second parameter which is its starting point.

If you have date("Ymdhis", $somedate) and wanted to add 30 minutes to it, you can do date("Ymdhis", strtotime("+30 minutes", $someddate))

answered Mar 22, 2012 at 22:57

staticsanstaticsan

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Try something like.

$Start = "12:00:00";
$Minutes = 30;

$To = date("H:i:s", strtotime($Start)+($Minutes*60));

answered Mar 22, 2012 at 22:51

AdamAdam

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Use this function:

date("Ymdhis", strtotime("+30 minutes"))

Somnath Muluk

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answered Mar 22, 2012 at 22:57

sikandersikander

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Not sure what your entire code looks like, but:

date("Ymdhis");

is returning a string. So it doesn't make sense to add the result of

strtotime("+30 minutes");

(which is an integer) to that string.

You either want

strtotime("+30 minutes");

by itself, or

date("Ymdhis", strtotime("+30 minutes"));

to get the formatted string.

answered Mar 22, 2012 at 22:56

mattmatt

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1

Do you mean date("Ymdhis", strtotime("+30 minutes"));? This will represent the date that is 30 minutes in the future.

answered Mar 22, 2012 at 22:57

mvdnesmvdnes

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answered Mar 22, 2012 at 23:05

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