Print odd numbers from 1 to 100 in python using while loop

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Given a list of numbers, write a Python program to print all odd numbers in given list. Example:

Input: list1 = [2, 7, 5, 64, 14]
Output: [7, 5]

Input: list2 = [12, 14, 95, 3, 73]
Output: [95, 3, 73]

1. Using for loop : Iterate each element in the list using for loop and check if num % 2 != 0. If the condition satisfies, then only print the number. 

Python3

list1 = [10, 21, 4, 45, 66, 93]

for num in list1:

    if num % 2 != 0:

       print(num, end = " ")

1. Output:

21 45 93 

1. Using while loop : 

Python3

list1 = [10, 21, 4, 45, 66, 93]

i = 0

while(i < len(list1)):

    if list1[i] % 2 != 0:

        print(list1[i], end = " ")

    i += 1

1. Output:

21 45 93 

1. Using list comprehension : 

Python3

list1 = [10, 21, 4, 45, 66, 93]

only_odd = [num for num in list1 if num % 2 == 1]

print(only_odd)

1. Output:

21 45 93 

1. Using lambda expressions :

Python3

list1 = [10, 21, 4, 45, 66, 93, 11]

odd_nos = list(filter(lambda x: (x % 2 != 0), list1))

print("Odd numbers in the list: ", odd_nos)

1. Output:

Odd numbers in the list:  [21, 45, 93, 11]

Method: Using pass 

Python3

lst=[10,21,4,45,66,93,11]

for i in lst:

  if i%2==0:

    pass

  else:

    print(i,end=" ")

Method: Using recursion 

Python3

def oddnumbers(list, n=0):

    if n==len(list):

        exit()

    if list[n]%2!=0:

        print(list[n], end=" ")

    oddnumbers(list, n+1)

list1 = [10, 21, 4, 45, 66, 93,11]

print("odd numbers in the list:", end=" ")

oddnumbers(list1)

Output

odd numbers in the list: 21 45 93 11 

Method: Using enumerate function 

Python3

list1 = [2, 7, 5, 64, 14]

for a,i in enumerate(list1):

  if i%2!=0:

    print(i,end=" ")

Auxiliary Space: O(1)