Python assign object to another object

You're pretty close here, but you have two problems.

First, your add_student and remove_student methods are trying to mutate some dictionary named self.student, but you forgot to create it. Do that in the __init__ method, like this:

def __init__[self, courseName, capacity]:
    # existing stuff
    self.student = {}

Next, your add_student needs to actually take a value parameter if you want to use it:

def add_student[self, key, value]:
    self.student[key] = value

And that's it. Now you can write code like this:

johnsmith = student['John', 'Smith', 14, 3.5]
intropython = course['Python 1', 20]
intropython.add_student['John Smith', johnsmith]

Of course you'll probably want to add more stuff to this later—e.g., a way to get a default key for a student [like his first and last names], checking whether len[self.student] == self.capacity before adding another student, etc. But this should get you started.

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    Prerequisite: Basics of OOPs in Python

    In this article, we will learn how to access object methods and attributes within other objects in Python. If we have two different classes and one of these defined another class on calling the constructor. Then, the method and attributes of another class can be accessed by first class objects [ i.e; objects within objects ].

    Here in the below example we learn to access object [its methods and attributes] within an object. We define two classes [class first and class second] with proper definitions. 

    • First class consists of a constructor and a method.
    • The constructor form an object of the second class in the attribute of the first class.
    • The method defines the presence in first class method.
    • Similarly, the second class consists of a constructor and a method.
    • The constructor form an attribute.
    • The method defines the presence in the second class method.

    As the attribute of first class work as an object of the second class so all the methods and attributes of the second class can be accessed using this:

    object_of_first_class.attribute_of_first_class
    

    Below is the implementation:

    Python3

    class first:

        def __init__[self]:

            self.fst = second[]

        def first_method[self]:

            print["Inside first method"]

    class second:

        def __init__[self]:

            self.snd = "GFG"

        def second_method[self]:

            print["Inside second method"]

    obj1 = first[]

    print[obj1]

    obj2 = obj1.fst

    print[obj2]

    print[obj2.snd]

    obj2.second_method[]

    Output:

    
    GFG  
    Inside second method
    

    Copy an Object in Python

    In Python, we use = operator to create a copy of an object. You may think that this creates a new object; it doesn't. It only creates a new variable that shares the reference of the original object.

    Let's take an example where we create a list named old_list and pass an object reference to new_list using = operator.

    Example 1: Copy using = operator

    old_list = [[1, 2, 3], [4, 5, 6], [7, 8, 'a']]
    new_list = old_list
    
    new_list[2][2] = 9
    
    print['Old List:', old_list]
    print['ID of Old List:', id[old_list]]
    
    print['New List:', new_list]
    print['ID of New List:', id[new_list]]

    When we run above program, the output will be:

    Old List: [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
    ID of Old List: 140673303268168
    
    New List: [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
    ID of New List: 140673303268168

    As you can see from the output both variables old_list and new_list shares the same id i.e 140673303268168.

    So, if you want to modify any values in new_list or old_list, the change is visible in both.

    Essentially, sometimes you may want to have the original values unchanged and only modify the new values or vice versa. In Python, there are two ways to create copies:

    1. Shallow Copy
    2. Deep Copy

    To make these copy work, we use the copy module.

    Copy Module

    We use the copy module of Python for shallow and deep copy operations. Suppose, you need to copy the compound list say x. For example:

    import copy
    copy.copy[x]
    copy.deepcopy[x]

    Here, the copy[] return a shallow copy of x. Similarly, deepcopy[] return a deep copy of x.

    Shallow Copy

    A shallow copy creates a new object which stores the reference of the original elements.

    So, a shallow copy doesn't create a copy of nested objects, instead it just copies the reference of nested objects. This means, a copy process does not recurse or create copies of nested objects itself.

    Example 2: Create a copy using shallow copy

    import copy
    
    old_list = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
    new_list = copy.copy[old_list]
    
    print["Old list:", old_list]
    print["New list:", new_list]

    When we run the program , the output will be:

    Old list: [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
    New list: [[1, 2, 3], [4, 5, 6], [7, 8, 9]]

    In above program, we created a nested list and then shallow copy it using copy[] method.

    This means it will create new and independent object with same content. To verify this, we print the both old_list and new_list.

    To confirm that new_list is different from old_list, we try to add new nested object to original and check it.

    Example 3: Adding [4, 4, 4] to old_list, using shallow copy

    import copy
    
    old_list = [[1, 1, 1], [2, 2, 2], [3, 3, 3]]
    new_list = copy.copy[old_list]
    
    old_list.append[[4, 4, 4]]
    
    print["Old list:", old_list]
    print["New list:", new_list]

    When we run the program, it will output:

    Old list: [[1, 1, 1], [2, 2, 2], [3, 3, 3], [4, 4, 4]]
    New list: [[1, 1, 1], [2, 2, 2], [3, 3, 3]]

    In the above program, we created a shallow copy of old_list. The new_list contains references to original nested objects stored in old_list. Then we add the new list i.e [4, 4, 4] into old_list. This new sublist was not copied in new_list.

    However, when you change any nested objects in old_list, the changes appear in new_list.

    Example 4: Adding new nested object using Shallow copy

    import copy
    
    old_list = [[1, 1, 1], [2, 2, 2], [3, 3, 3]]
    new_list = copy.copy[old_list]
    
    old_list[1][1] = 'AA'
    
    print["Old list:", old_list]
    print["New list:", new_list]

    When we run the program, it will output:

    Old list: [[1, 1, 1], [2, 'AA', 2], [3, 3, 3]]
    New list: [[1, 1, 1], [2, 'AA', 2], [3, 3, 3]]

    In the above program, we made changes to old_list i.e old_list[1][1] = 'AA'. Both sublists of old_list and new_list at index [1][1] were modified. This is because, both lists share the reference of same nested objects.

    Deep Copy

    A deep copy creates a new object and recursively adds the copies of nested objects present in the original elements.

    Let’s continue with example 2. However, we are going to create deep copy using deepcopy[] function present in copy module. The deep copy creates independent copy of original object and all its nested objects.

    Example 5: Copying a list using deepcopy[]

    import copy
    
    old_list = [[1, 1, 1], [2, 2, 2], [3, 3, 3]]
    new_list = copy.deepcopy[old_list]
    
    print["Old list:", old_list]
    print["New list:", new_list]

    When we run the program, it will output:

    Old list: [[1, 1, 1], [2, 2, 2], [3, 3, 3]]
    New list: [[1, 1, 1], [2, 2, 2], [3, 3, 3]]

    In the above program, we use deepcopy[] function to create copy which looks similar.

    However, if you make changes to any nested objects in original object old_list, you’ll see no changes to the copy new_list.

    Example 6: Adding a new nested object in the list using Deep copy

    import copy
    
    old_list = [[1, 1, 1], [2, 2, 2], [3, 3, 3]]
    new_list = copy.deepcopy[old_list]
    
    old_list[1][0] = 'BB'
    
    print["Old list:", old_list]
    print["New list:", new_list]

    When we run the program, it will output:

    Old list: [[1, 1, 1], ['BB', 2, 2], [3, 3, 3]]
    New list: [[1, 1, 1], [2, 2, 2], [3, 3, 3]]

    In the above program, when we assign a new value to old_list, we can see only the old_list is modified. This means, both the old_list and the new_list are independent. This is because the old_list was recursively copied, which is true for all its nested objects.

    How do you assign one object to another object in Python?

    In Python, we use = operator to create a copy of an object. You may think that this creates a new object; it doesn't. It only creates a new variable that shares the reference of the original object. Let's take an example where we create a list named old_list and pass an object reference to new_list using = operator.

    Can we assign an object to another object of same class?

    You can have multiple variables pointing to the same object; setting one of them to null doesn't make the object itself unavailable.

    Can we assign one object to another?

    If we use the assignment operator to assign an object reference to another reference variable then it will point to the same address location of the old object and no new copy of the object will be created. Due to this any changes in the reference variable will be reflected in the original object.

    Can an object be an attribute of another object?

    Yes. Show activity on this post. You can have both instances and classes as attributes of both classes and instances -- all four combinations work just fine [and can be combined freely].

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