A quick no-brainer:
some_float = 1234.5678
print '%02d' % some_float # 1234
some_float = 1234.5678
print '{WHAT?}'.format[some_float] # I want 1234 here too
Note: {:.0f}
is not an option, because it rounds [returns 1235
in this example].
format[..., int[some_float]]
is exactly the thing I'm trying to avoid, please don't suggest that.
Asclepius
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asked Nov 22, 2012 at 11:19
6
It's worth mentioning the built in behavior for how floats are rendered using the raw format strings. If you know in advance where your fractional part lies with respect to 0.5 you can leverage the format string you originally attempted but discovered it fell short from rounding side effects "{:0.0f}"
. Check out the following examples...
>>> "{:0.0f}".format[1.999]
'2'
>>> "{:0.0f}".format[1.53]
'2'
>>> "{:0.0f}".format[1.500]
'2'
>>> "{:0.0f}".format[1.33]
'1'
>>> "{:0.0f}".format[0.501]
'1'
>>> "{:0.0f}".format[0.5]
'0'
>>> "{:0.0f}".format[0.1]
'0'
>>> "{:0.0f}".format[0.001]
'0'
As you can see there's rounding behavior behind the scenes. In my case where I had a database converting ints to floats I knew I was dealing with a non fractional part in advance and only wanted to render in an html template the int portion of the float as a workaround. Of course if you don't know in advance the fractional part you would need to carry out a truncation operation of some sort first on the float.
answered Mar 7, 2019 at 19:21
jxramosjxramos
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It's possible to extend the standard string formatting language by extending the class string.Formatter:
class MyFormatter[Formatter]:
def format_field[self, value, format_spec]:
if format_spec == 't': # Truncate and render as int
return str[int[value]]
return super[MyFormatter, self].format_field[value, format_spec]
MyFormatter[].format["{0} {1:t}", "Hello", 4.567] # returns "Hello 4"
answered Nov 22, 2012 at 13:49
berealbereal
30.2k6 gold badges53 silver badges93 bronze badges
0
This works:
from math import trunc
some_float = 1234.5678
print '{:d}'.format[trunc[some_float]]
=> 1234
Or just do this, for that matter:
print trunc[some_float]
=> 1234
I think it's an acceptable answer, it avoids the conversion to int
. Notice that in this snippet: '%02d' % some_float
an implicit conversion to int
is happening, you can't avoid some sort of conversion for printing in the desired format.
answered Nov 22, 2012 at 11:25
Óscar LópezÓscar López
227k35 gold badges302 silver badges376 bronze badges
This will work too:
some_float = 1234.5678
f = lambda x: str[x][:str[x].find['.']]
print '{}'.format[f[some_float]]
=> 1234
After doing a %timeit test it looks like this is a bit faster than the trunc method.
answered Dec 3, 2015 at 8:35
5
Not the answer you're looking for? Browse other questions tagged python format or ask your own question.
Converting a float value to an int is done by Type conversion, which is an explicit method of converting an operand to a specific type. However, it is to be noted that such type of conversion may tend to be a lossy one [loss of data]. Converting an int value like 2 to floating-point will result in 2.0, such types of
conversion are safe as there would be no loss of data, but converting 3.4 to an int value will result in 3 leading to a lossy conversion.
Examples:
Input: 3.3 Output: 3 Input: 5.99 Output: 5
Method 1: Conversion using int[]:
To convert a float value to int we make use of the built-in int[] function, this function trims the values after the decimal point and returns only the integer/whole number part.
Syntax: int[x]
Return: integer value
Example 1: Number of type float is converted to a result of type int.
Python3
num
=
9.3
print
[
'type:'
,
type
[num].__name__]
num
=
int
[num]
print
[
'converted value:'
, num,
', type:'
,
type
[num].__name__]
Output
type: float converted value: 9 , type: int
Example 2: In most cases the int[] function rounds off the result to an integer lesser than or equal to the input, but the behavior is neither definite nor predictable. One such example is shown below.
Python3
num1
=
5.9
num2
=
5.99999999999999999999
num1
=
int
[num1]
num2
=
int
[num2]
print
[num1, num2, sep
=
'\n'
]
Method 2: Conversion using math.floor[] and math.ceil[].
A float value can be converted to an int value no larger than the input by using the math.floor[] function, whereas it can also be converted to an int value which is the smallest integer greater than the input using math.ceil[] function. The math module is to be imported in order to use these methods.
Syntax: math.floor[x]
Parameter:
x: This is a numeric expression.
Returns: largest integer not greater than x.
Syntax: math.ceil[x]
Parameter:
x: This is a numeric expression.
Returns: Smallest integer not less than x.
Example : In the below example conversion from float to int has been achieved using the floor[] and ceil[] methods, the former returns an int no larger than the input and the latter returns the smallest integer larger than the input.
Python3
import
math
num
=
5.6
floor_value
=
math.floor[num]
ceil_value
=
math.ceil[num]
print
[
"the result using floor[] : "
,
floor_value ,
', type : '
,
type
[floor_value].__name__]
print
[
"the result using ceil[] : "
,
ceil_value,
', type: '
,
type
[ceil_value].__name__]
Output
the result using floor[] : 5 , type : int the result using ceil[] : 6 , type: int
Method#3: Conversion using round[ ].
A float value can be converted to an int value which is closet integer value if does not pass second parameter. In case of equal difference it goes toward larger integer.
Syntax: round[x]
Parameter:
x: This is a numeric expression.
Returns: integer multiple of closest.
Example : In the below example conversion from float to int has been achieved using the round[] methods, the former returns an int number which is closest to number.
Python3
num
=
5.6
print
[
'Type : '
,
type
[num].__name__]
print
[
"Original number is : "
, num]
value
=
round
[num]
print
[
'Type : '
,
type
[value].__name__]
print
[
"the result using round : "
,value]
Output
Type : float Original number is : 5.6 Type : int the result using round : 6
Method#4: Conversion using math.trunc[ ].
A float value can be converted to an int value. In case of negative number it behaves like ceiling function of math library and in case of positive number it behaves like floor function..
Syntax: math.trunc[x]
Parameter:
x: This is a numeric expression.
Returns: larger integer in case of negative number else in case of positive number smaller number.
Example : In the below example conversion from float to int has been achieved using the math.trunc[] methods, the former returns an larger int number which in case of negative number, else in case of positive number return smaller integer number.
Python3
import
math
num
=
5.6
num2
=
-
2.6
value
=
math.trunc[num2]
print
[
'Type of value : '
,
type
[value].__name__]
print
[
"the result using round : "
,value]
data
=
math.trunc[num]
print
[
'Type of data: '
,
type
[data].__name__]
print
[
"the result using round : "
,data]
Output
Type of value : int the result using round : -2 Type of data: int the result using round : 5