Write a program to print odd numbers from 1 to 100 using while loop in python

View Discussion

Improve Article

Save Article

  • Read
  • Discuss
  • View Discussion

    Improve Article

    Save Article

    Given a list of numbers, write a Python program to print all odd numbers in given list. 

    Example:

    Input: list1 = [2, 7, 5, 64, 14]
    Output: [7, 5]
    
    Input: list2 = [12, 14, 95, 3, 73]
    Output: [95, 3, 73]

    Using for loop : Iterate each element in the list using for loop and check if num % 2 != 0. If the condition satisfies, then only print the number. 

    Python3

    list1 = [10, 21, 4, 45, 66, 93]

    for num in list1:

        if num % 2 != 0:

        print(num, end=" ")

    Output:

    21 45 93 

    Using while loop : 

    Python3

    list1 = [10, 21, 4, 45, 66, 93]

    i = 0

    while(i < len(list1)):

        if list1[i] % 2 != 0:

            print(list1[i], end=" ")

        i += 1

    Output:

    21 45 93 

    Using list comprehension

    Python3

    list1 = [10, 21, 4, 45, 66, 93]

    only_odd = [num for num in list1 if num % 2 == 1]

    print(only_odd)

    Output:

    21 45 93 

    Using lambda expressions :

    Python3

    list1 = [10, 21, 4, 45, 66, 93, 11]

    odd_nos = list(filter(lambda x: (x % 2 != 0), list1))

    print("Odd numbers in the list: ", odd_nos)

    Output:

    Odd numbers in the list:  [21, 45, 93, 11]

    Method: Using pass 

    Python3

    lst = [10, 21, 4, 45, 66, 93, 11]

    for i in lst:

        if i % 2 == 0:

            pass

        else:

            print(i, end=" ")

    Method: Using recursion 

    Python3

    def oddnumbers(list, n=0):

        if n == len(list):

            exit()

        if list[n] % 2 != 0:

            print(list[n], end=" ")

        oddnumbers(list, n+1)

    list1 = [10, 21, 4, 45, 66, 93, 11]

    print("odd numbers in the list:", end=" ")

    oddnumbers(list1)

    Output

    odd numbers in the list: 21 45 93 11 

    Method: Using enumerate function 

    Python3

    list1 = [2, 7, 5, 64, 14]

    for a,i in enumerate(list1):

      if i%2!=0:

        print(i,end=" ")

    Auxiliary Space: O(1)

    Method: Using numpy.array function

    Python3

    import numpy as np

    list1 = np.array([10, 21, 4, 45, 66, 93])

    only_odd = list1[list1 % 2 == 1]

    print(only_odd)

    Output:

    [21 45 93]

    How do you print a odd number in a while loop in Python?

    Use the python input() function that allows the user to enter the maximum limit value. Next, Run for a loop and Add the current value of n to num variable. Next, Python is going to print even and odd numbers from 1 to the user entered a maximum limit value.

    How do you print odd numbers from 1 to N in Python?

    Python3.
    start = int ( input ( "Enter the start of range:" )) end = int ( input ( "Enter the end of range:" )).
    # iterating each number in list. for num in range (start, end + 1 ):.
    # checking condition. if num % 2 ! = 0 : print (num).

    How do you find the odd number in a while loop?

    Using while loop by checking the condition number<=n (value of number is less than or equal to n) - this will execute the loop until the value of number is less than or equal to n. Then, within the loop, we are checking the condition to check whether number is ODD or not, the condition is (number%2 !=

    How do you write odd numbers in Python?

    num = int (input (“Enter any number to test whether it is odd or even: “) if (num % 2) == 0: print (“The number is even”) else: print (“The provided number is odd”) Output: Enter any number to test whether it is odd or even: 887 887 is odd.