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Given a list of numbers, write a Python program to print all odd numbers in given list.
Example:
Input: list1 = [2, 7, 5, 64, 14] Output: [7, 5] Input: list2 = [12, 14, 95, 3, 73] Output: [95, 3, 73]
Using for loop : Iterate each element in the list using for loop and check if num % 2 != 0. If the condition satisfies, then only print the number.
Python3
list1 = [10, 21, 4, 45, 66, 93]
for num in list1:
if
num % 2 != 0:
print[num, end=" "]
Output:
21 45 93
Using while loop :
Python3
list1 =
[10, 21, 4, 45, 66, 93]
i = 0
while[i < len[list1]]:
if list1[i] % 2 != 0:
print[list1[i], end=" "]
i += 1
Output:
21 45 93
Using list comprehension :
Python3
list1 = [10, 21, 4, 45, 66, 93]
only_odd = [num for num in list1 if num % 2 == 1]
print[only_odd]
Output:
21 45 93
Using lambda expressions :
Python3
list1 = [10, 21, 4, 45, 66, 93, 11]
odd_nos = list[filter[lambda x: [x % 2 != 0], list1]]
print["Odd numbers in the list: ", odd_nos]
Output:
Odd numbers in the list: [21, 45, 93, 11]
Method: Using pass
Python3
lst = [10, 21, 4, 45, 66, 93, 11]
for i in lst:
if i % 2 == 0:
pass
else:
print[i, end=" "]
Method: Using recursion
Python3
def oddnumbers[list, n=0]:
if n == len[list]:
exit[]
if list[n] % 2 != 0:
print[list[n], end=" "]
oddnumbers[list, n+1]
list1 =
[10, 21, 4, 45, 66, 93, 11]
print["odd numbers in the list:", end=" "]
oddnumbers[list1]
Output
odd numbers in the list: 21 45 93 11
Method: Using enumerate function
Python3
list1 =
[2, 7, 5, 64, 14]
for a,i in enumerate[list1]:
if i%2!=0:
print[i,end=" "]
Auxiliary Space: O[1]
Method: Using numpy.array function
Python3
import numpy as np
list1 = np.array[[10, 21, 4, 45, 66, 93]]
only_odd = list1[list1 % 2 == 1]
print[only_odd]
Output:
[21 45 93]