How can i get month in php?

I want to be able to figure out the month of the current date variable. I'm ex vb.net and the way to do it there is just date.Month. How do I do this in PHP?

Thanks,

Jonesy

I used date_format[$date, "m"]; //01, 02..12

This is what I wanted, question now is how do I compare this to an int since $monthnumber = 01 just becomes 1

John

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asked Sep 22, 2010 at 9:51

iamjonesyiamjonesy

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See //php.net/date

date['m'] or date['n'] or date['F'] ...

Update

m Numeric representation of a month, with leading zeros 01 through 12

n Numeric representation of a month, without leading zeros 1 through 12

F Alphabetic representation of a month January through December

....see the docs link for even more options.

answered Sep 22, 2010 at 9:54

What does your "data variable" look like? If it's like this:

$mydate = "2010-05-12 13:57:01";

You can simply do:

$month = date["m",strtotime[$mydate]];

For more information, take a look at date and strtotime.

EDIT:

To compare with an int, just do a date_format[$date,"n"]; which will give you the month without leading zero.

Alternatively, try one of these:

if[[int]$month == 1]...
if[abs[$month] == 1]...

Or something weird using ltrim, round, floor... but date_format[] with "n" would be the best.

Kwido

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answered Sep 22, 2010 at 9:56

oezioezi

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$unixtime = strtotime[$test];
echo date['m', $unixtime]; //month
echo date['d', $unixtime]; 
echo date['y', $unixtime ];

answered Sep 22, 2010 at 9:56

Pramendra GuptaPramendra Gupta

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as date_format uses the same format as date [ //www.php.net/manual/en/function.date.php ] the "Numeric representation of a month, without leading zeros" is a lowercase n .. so

echo date['n']; // "9"

answered Sep 22, 2010 at 10:45

HannesHannes

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As it's not specified if you mean the system's current date or the date held in a variable, I'll answer for latter with an example.

answered Apr 7, 2018 at 4:59

J-a-n-u-sJ-a-n-u-s

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To compare with an int do this:

answered Feb 29, 2020 at 16:20

e102e102

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