Example 1: Count Number of Digits in an Integer using while loop
num = 3452
count = 0
while num != 0:
num //= 10
count += 1
print["Number of digits: " + str[count]]Output
Number of digits: 4
In this program, the while loop is iterated until the test expression num != 0 is evaluated to 0 [false].
- After the first iteration,
numwill be divided by 10 and its value will be 345. Then, thecountis incremented to 1. - After the second iteration, the value of
numwill be 34 and thecountis incremented to 2. - After the third
iteration, the value of
numwill be 3 and thecountis incremented to 3. - After the fourth iteration, the value of
numwill be 0 and thecountis incremented to 4. - Then the test expression is evaluated to false and the loop terminates.
Example 2: Using inbuilt methods
num = 123456
print[len[str[num]]]Output
6
In the above example, we first convert the integer value into string by using str[]. Then, we find the length of the string using
len[].
I have some floating point values in Python. I would like to print them so that the have the same number of digits [sum of the integer and decimal parts]
For example considering the two numbers:
a = 12.123456
b = 123.1234567
I would like to print their value formatted as follows:
12.1234
123.123
So that they have the same length.
One simple way is the following:
if [val>100]:
print["%0.3f" % val]
else:
print["%0.4f" % val]
Is there a smarter way to control both the number of integer and decimal digits at the same time in python so that the resulting string is constant?
This is a Python Program to count the number of digits in a number. Problem Description The program takes the number and prints the number of digits in the number. Problem Solution
1. Take the value of the integer and store in a variable.
2. Using a while loop, get each digit of the number and increment the count each time a digit is
obtained.
3. Print the number of digits in the given integer.
4. Exit.
Program/Source Code
Here is source code of the Python Program to count the number of digits in a number. The program output is also shown below.
n=int[input["Enter number:"]] count=0 while[n>0]: count=count+1 n=n//10 print["The number of digits in the number are:",count]
Program Explanation
1. User must first enter the value of the integer and store it in a variable.
2. The while loop is used and the last digit of the number is obtained by using the modulus operator.
3. Each time a digit is
obtained, the count value is incremented.
4. This loop terminates when the value of the number is 0.
5. The total count of the number of digits is printed.
Runtime Test Cases
Case 1: Enter number:123 The number of digits in the number are: 3 Case 2: Enter number:1892 The number of digits in the number are: 4
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