How do you split a number into two parts in python?

How do I split a number into two without any arithmetic in python? For example, the table below:

20670005000000
30003387889032
44555008000004

I want the string to look like the columns below after splitting [and remain numbers that can be used in numerical analysis]:

2067000  5000000
3000338  7889032
4455500  8000004

What's the neatest way to do this in Python? Is there a python module that deals with this directly?

asked Oct 12, 2017 at 14:51

5

This is a possible way:

N = 10000000
i = 20670005000000

# The first part of the number i
i // N
# the second part
i % N

answered Oct 12, 2017 at 14:56

elzellelzell

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1

I don't know if it is the best way, but you can convert to string, than split it, and convert it to integer again:

number = [int[str[number][:len[number]/2]], int[str[number][len[number]/2:]]]

This will give you a touple which you can use later. You can further optimize this by using list comprehension.

answered Oct 12, 2017 at 14:56

It seems that the existing pattern of operation in this problem is to divide each string value in half.

import re
s = [20670005000000, 30003387889032, 44555008000004]
final_string = [map[int, re.findall['.{'+str[len[str[i]]//2]+'}', str[i]]] for i in s]

Output:

[[2067000, 5000000], [3000338, 7889032], [4455500, 8000004]]

answered Oct 12, 2017 at 14:59

Ajax1234Ajax1234

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you could map the int to str, then split it. remember convert it back to int

  data = [20670005000000,
        30003387889032,
        44555008000004,]

  str_data = map[str, data]
  res = map[lambda x: [x[:len[x]//2],x[len[x]//2:]], str_data ]
  res = map[int, reduce[lambda x,y: x+y, res] ]
  print res

output:

[2067000, 5000000, 3000338, 7889032, 4455500, 8000004]

answered Oct 12, 2017 at 14:59

galaxyangalaxyan

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2

Assuming the number should be divided exactly at center each time, we can use string and slicing of it to get the two numbers.

Doing with single number here :

>>> s = str[20670005000000]
>>> l = int[len[s]/2]
>>> a,b = s[:l],s[l:]
>>> int[a]
=>  2067000   
>>> int[b]
=>  5000000

Here, for the List of numbers :

for ele in map[str,arr]: 
   l = int[ len[ele]/2 ] 
   a,b = ele[:l], ele[l:]

   print[int[a], int[b]] 

# driver values

IN : arr = [20670005000000, 30003387889032, 44555008000004]

OUT : 2067000 5000000
      3000338 7889032
      4455500 8000004

answered Oct 12, 2017 at 14:58

Kaushik NPKaushik NP

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Assuming str.len[] does not involve arithmetic and comparing two integers [2 > 3] is NOT arithmetic:

import collections
n = 20670005000000

left = collections.deque[str[n]]
right = collections.deque[]
while len[left] > len[right]:
    right.appendleft[left.pop[]]

left = int[''.join[left]]
right = int[''.join[right]]

answered Oct 12, 2017 at 15:30

wwiiwwii

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