How to get day of the week in php?

If I've got a $date YYYY-mm-dd and want to get a specific $day [specified by 0 [sunday] to 6 [saturday]] of the week that YYYY-mm-dd is in.

For example, if I got 2012-10-11 as $date and 5 as $day, I want to get 2012-10-12, if I've got 0 as $day, 2012-10-14

EDIT:
Most of you misunderstood it. I got some date, $date and want to get a day specified by 0-6 of the same week $date is in.

So no, I don't want the day of $date...

SparK

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asked Oct 11, 2012 at 8:17

2

I think this is what you want.

$dayofweek = date['w', strtotime[$date]];
$result    = date['Y-m-d', strtotime[[$day - $dayofweek].' day', strtotime[$date]]];

answered Oct 11, 2012 at 8:35

RezignedRezigned

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0

You can use the date[] function:

date['w']; // day of week

or

date['l']; // dayname

Example function to get the day nr.:

function getWeekday[$date] {
    return date['w', strtotime[$date]];
}

echo getWeekday['2012-10-11']; // returns 4

answered Oct 11, 2012 at 8:20

powtacpowtac

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Try

$date = '2012-10-11';
$day  = 1;
$days = array['Sunday', 'Monday', 'Tuesday', 'Wednesday','Thursday','Friday', 'Saturday'];
echo date['Y-m-d', strtotime[$days[$day], strtotime[$date]]];

answered Oct 11, 2012 at 8:30

air4xair4x

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2

If your date is already a DateTime or DateTimeImmutable you can use the format method.

$day_of_week = intval[$date_time->format['w']];

The format string is identical to the one used by the date function.

To answer the intended question:

$date_time->modify[$target_day_of_week - $day_of_week . ' days'];

answered Sep 17, 2018 at 8:46

PHP Manual said :

w Numeric representation of the day of the week

You can therefore construct a date with mktime, and use in it date["w", $yourTime];

answered Oct 11, 2012 at 8:21

blue112blue112

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0

Just:

2012-10-11 as $date and 5 as $day

The $result = '2012-10-12' is what you want.

answered Oct 11, 2012 at 8:32

lijinmalijinma

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I'm afraid you have to do it manually. Get the date's current day of week, calculate the offset and add the offset to the date.

$current = date["w", $date]
$offset = $day - $current
$new_date = new DateTime[$date]
    ->add[
        new DateInterval[$offset."D"]
    ]->format['Y-m-d']

answered Oct 11, 2012 at 8:29

John DvorakJohn Dvorak

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1

I had to use a similar solution for Portuguese [Brazil]: