Hướng dẫn distance between two points python - khoảng cách giữa hai điểm python

Chúng ta đừng quên Math.hypot:

dist = math.hypot[x2-x1, y2-y1]

Đây là Hypot như là một phần của đoạn trích để tính độ dài của đường dẫn được xác định bởi danh sách các bộ dữ liệu [x, y]:

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

x = [1, 2, 3, 4, 5]
result = []
for idx in range[len[x]]:
    result.append[x[idx] * 2]
result

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

[2, 4, 6, 8, 10]

[2, 4, 6, 8, 10]

[2, 4, 6, 8, 10]

x = [1, 2, 3, 4, 5]
result = []
for idx in range[len[x]]:
    result.append[x[idx] * 2]
result

[2, 4, 6, 8, 10]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

x = [1, 2, 3, 4, 5]
result = []
for idx in range[len[x]]:
    result.append[x[idx] * 2]
result

[2, 4, 6, 8, 10]

[2, 4, 6, 8, 10]

[[element * 2] for element in x]

[2, 4, 6, 8, 10]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

[[element * 2] for element in x]

444565

import math
p1 = [4, 0]
p2 = [6, 6]
distance = math.sqrt[ [[p1[0]-p2[0]]**2]+[[p1[1]-p2[1]]**2] ]

print[distance]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

[[element * 2] for element in x]

Mã số 3:

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

4
from math import hypot pts = [ [10,10], [10,11], [20,11], [20,10], [10,10], ] # Py2 syntax - no longer allowed in Py3 # ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]] ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]] diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]] path = sum[hypot[*d] for d in diffs] print[path]
5
x = [1, 2, 3, 4, 5] result = [] for idx in range[len[x]]: result.append[x[idx] * 2] result
9
from math import hypot pts = [ [10,10], [10,11], [20,11], [20,10], [10,10], ] # Py2 syntax - no longer allowed in Py3 # ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]] ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]] diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]] path = sum[hypot[*d] for d in diffs] print[path]
6
[2, 4, 6, 8, 10]
1
x = [1, 2, 3, 4, 5] result = [] for idx in range[len[x]]: result.append[x[idx] * 2] result
1
[2, 4, 6, 8, 10]
1
6.324555320336759
3
[2, 4, 6, 8, 10]
1
[[element * 2] for element in x]
4445:-

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

7
from math import hypot pts = [ [10,10], [10,11], [20,11], [20,10], [10,10], ] # Py2 syntax - no longer allowed in Py3 # ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]] ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]] diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]] path = sum[hypot[*d] for d in diffs] print[path]
5
x = [1, 2, 3, 4, 5] result = [] for idx in range[len[x]]: result.append[x[idx] * 2] result
9
from math import hypot pts = [ [10,10], [10,11], [20,11], [20,10], [10,10], ] # Py2 syntax - no longer allowed in Py3 # ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]] ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]] diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]] path = sum[hypot[*d] for d in diffs] print[path]
9
6.324555320336759
7
[2, 4, 6, 8, 10]
1
from math import hypot pts = [ [10,10], [10,11], [20,11], [20,10], [10,10], ] # Py2 syntax - no longer allowed in Py3 # ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]] ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]] diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]] path = sum[hypot[*d] for d in diffs] print[path]
9
from math import hypot pts = [ [10,10], [10,11], [20,11], [20,10], [10,10], ] # Py2 syntax - no longer allowed in Py3 # ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]] ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]] diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]] path = sum[hypot[*d] for d in diffs] print[path]
6
[2, 4, 6, 8, 10]
1
from math import hypot pts = [ [10,10], [10,11], [20,11], [20,10], [10,10], ] # Py2 syntax - no longer allowed in Py3 # ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]] ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]] diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]] path = sum[hypot[*d] for d in diffs] print[path]
9
x = [1, 2, 3, 4, 5] result = [] for idx in range[len[x]]: result.append[x[idx] * 2] result
1
[2, 4, 6, 8, 10]
1____61__1

import math
p1 = [4, 0]
p2 = [6, 6]
distance = math.sqrt[ [[p1[0]-p2[0]]**2]+[[p1[1]-p2[1]]**2] ]

print[distance]

Tham khảo: Thư viện toán học Python

6.324555320336759

Flowchart:

Cập nhật lần cuối vào ngày 19 tháng 8 năm 2022 21:51:50 [UTC/GMT +8 giờ]

Python Basic: Tập thể dục-40 với giải pháp

Viết một chương trình Python để tính khoảng cách giữa các điểm [x1, y1] và [x2, y2].

Trình bày bằng hình ảnh:

Giải pháp mẫu:- Write a Python program to compute the future value of a specified principal amount, rate of interest, and a number of years.
Next: Write a Python program to check whether a file exists.

Mã Python:

Đầu ra mẫu:

Trực quan hóa thực thi mã Python:

Công cụ sau đây trực quan hóa những gì máy tính đang làm từng bước khi nó thực hiện chương trình đã nói:

x = [1, 2, 3, 4, 5]
result = []
for idx in range[len[x]]:
    result.append[x[idx] * 2]
result

Output:

[2, 4, 6, 8, 10]

[[element * 2] for element in x]

Output:

Trình chỉnh sửa mã Python:

Có một cách khác để giải quyết giải pháp này? Đóng góp mã của bạn [và nhận xét] thông qua Disqus.
Trước đây: Viết một chương trình Python để tính toán giá trị tương lai của một số tiền gốc được chỉ định, lãi suất và một số năm.
Mức độ khó của bài tập này là gì?
Kiểm tra kỹ năng lập trình của bạn với bài kiểm tra của W3Resource.
Python: Lời khuyên trong ngày
Sử dụng toàn bộ danh sách để rút ngắn cho các vòng lặp:
```
[2, 4, 6, 8, 10]
```
Bài tập: Top 16 chủ đề phổ biến nhất hàng tuần
Bài tập SQL, Thực hành, Giải pháp - Tham gia
Bài tập SQL, Thực hành, Giải pháp - Quan sát phụ
JavaScript Basic - Bài tập, Thực hành, Giải pháp
Java Array: Bài tập, Thực hành, Giải pháp
C Bài tập lập trình, Thực hành, Giải pháp: Tuyên bố có điều kiện
Cơ sở dữ liệu nhân sự - Sắp xếp bộ lọc: Bài tập, Thực hành, Giải pháp
C Bài tập lập trình, Thực hành, Giải pháp: Chuỗi
Các loại dữ liệu Python: Từ điển - Bài tập, Thực hành, Giải pháp
Câu đố lập trình Python - Bài tập, Thực hành, Giải pháp

Cải thiện bài viết

Lưu bài viết

Mô -đun toán học trong Python chứa một số thao tác toán học, có thể được thực hiện dễ dàng bằng cách sử dụng mô -đun. Phương pháp

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

0 trong Python được sử dụng cho khoảng cách Euclide giữa hai điểm P và Q, mỗi điểm được đưa ra như một chuỗi [hoặc có thể lặp lại] của tọa độ. Hai điểm phải có cùng một chiều. Phương pháp này mới trong Python phiên bản 3.8. in Python contains a number of mathematical operations, which can be performed with ease using the module.

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

0 method in Python is used to the Euclidean distance between two points p and q, each given as a sequence [or iterable] of coordinates. The two points must have the same dimension.
This method is new in Python version 3.8.

Cú pháp: Math.Dist [P, Q] math.dist[p, q]
Các tham số: P: Một chuỗi hoặc có thể lặp lại của tọa độ đại diện cho Pointq đầu tiên: một chuỗi hoặc có thể lặp lại của tọa độ đại diện cho điểm thứ hai
p: A sequence or iterable of coordinates representing first point
q: A sequence or iterable of coordinates representing second point
Trả về: Khoảng cách Euclide được tính toán giữa các điểm đã cho. the calculated Euclidean distance between the given points.

Mã số 1: Sử dụng phương thức

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

0 Use of

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

0 method

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

import math
p1 = [4, 0]
p2 = [6, 6]
distance = math.sqrt[ [[p1[0]-p2[0]]**2]+[[p1[1]-p2[1]]**2] ]

print[distance]

import math
p1 = [4, 0]
p2 = [6, 6]
distance = math.sqrt[ [[p1[0]-p2[0]]**2]+[[p1[1]-p2[1]]**2] ]

print[distance]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

import math
p1 = [4, 0]
p2 = [6, 6]
distance = math.sqrt[ [[p1[0]-p2[0]]**2]+[[p1[1]-p2[1]]**2] ]

print[distance]

import math
p1 = [4, 0]
p2 = [6, 6]
distance = math.sqrt[ [[p1[0]-p2[0]]**2]+[[p1[1]-p2[1]]**2] ]

print[distance]

import math
p1 = [4, 0]
p2 = [6, 6]
distance = math.sqrt[ [[p1[0]-p2[0]]**2]+[[p1[1]-p2[1]]**2] ]

print[distance]

Mã số 2:

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

import math
p1 = [4, 0]
p2 = [6, 6]
distance = math.sqrt[ [[p1[0]-p2[0]]**2]+[[p1[1]-p2[1]]**2] ]

print[distance]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

5 ________ 16 & nbsp;

6.324555320336759

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

6.324555320336759

6.324555320336759

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

6.324555320336759

6.324555320336759

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

x = [1, 2, 3, 4, 5]
result = []
for idx in range[len[x]]:
    result.append[x[idx] * 2]
result

import math
p1 = [4, 0]
p2 = [6, 6]
distance = math.sqrt[ [[p1[0]-p2[0]]**2]+[[p1[1]-p2[1]]**2] ]

print[distance]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

x = [1, 2, 3, 4, 5]
result = []
for idx in range[len[x]]:
    result.append[x[idx] * 2]
result

import math
p1 = [4, 0]
p2 = [6, 6]
distance = math.sqrt[ [[p1[0]-p2[0]]**2]+[[p1[1]-p2[1]]**2] ]

print[distance]

import math
p1 = [4, 0]
p2 = [6, 6]
distance = math.sqrt[ [[p1[0]-p2[0]]**2]+[[p1[1]-p2[1]]**2] ]

print[distance]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

x = [1, 2, 3, 4, 5]
result = []
for idx in range[len[x]]:
    result.append[x[idx] * 2]
result

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

[2, 4, 6, 8, 10]

[2, 4, 6, 8, 10]

[2, 4, 6, 8, 10]

x = [1, 2, 3, 4, 5]
result = []
for idx in range[len[x]]:
    result.append[x[idx] * 2]
result

[2, 4, 6, 8, 10]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

x = [1, 2, 3, 4, 5]
result = []
for idx in range[len[x]]:
    result.append[x[idx] * 2]
result

[2, 4, 6, 8, 10]

[2, 4, 6, 8, 10]

[[element * 2] for element in x]

[2, 4, 6, 8, 10]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

[[element * 2] for element in x]

444565

import math
p1 = [4, 0]
p2 = [6, 6]
distance = math.sqrt[ [[p1[0]-p2[0]]**2]+[[p1[1]-p2[1]]**2] ]

print[distance]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

[[element * 2] for element in x]

import math
p1 = [4, 0]
p2 = [6, 6]
distance = math.sqrt[ [[p1[0]-p2[0]]**2]+[[p1[1]-p2[1]]**2] ]

print[distance]

import math
p1 = [4, 0]
p2 = [6, 6]
distance = math.sqrt[ [[p1[0]-p2[0]]**2]+[[p1[1]-p2[1]]**2] ]

print[distance]

Output:

17.88854381999832
12.688577540449518

Mã số 3:

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

import math
p1 = [4, 0]
p2 = [6, 6]
distance = math.sqrt[ [[p1[0]-p2[0]]**2]+[[p1[1]-p2[1]]**2] ]

print[distance]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

5 ________ 16 & nbsp;

6.324555320336759

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

6.324555320336759

import math
p1 = [4, 0]
p2 = [6, 6]
distance = math.sqrt[ [[p1[0]-p2[0]]**2]+[[p1[1]-p2[1]]**2] ]

print[distance]

from math import hypot

pts = [
    [10,10],
    [10,11],
    [20,11],
    [20,10],
    [10,10],
    ]

# Py2 syntax - no longer allowed in Py3
# ptdiff = lambda [p1,p2]: [p1[0]-p2[0], p1[1]-p2[1]]
ptdiff = lambda p1, p2: [p1[0]-p2[0], p1[1]-p2[1]]

diffs = [ptdiff[p1, p2] for p1, p2 in zip [pts, pts[1:]]]
path = sum[hypot[*d] for d in  diffs]
print[path]

[[element * 2] for element in x]

import math
p1 = [4, 0]
p2 = [6, 6]
distance = math.sqrt[ [[p1[0]-p2[0]]**2]+[[p1[1]-p2[1]]**2] ]

print[distance]

import math
p1 = [4, 0]
p2 = [6, 6]
distance = math.sqrt[ [[p1[0]-p2[0]]**2]+[[p1[1]-p2[1]]**2] ]

print[distance]

Output:

21.93171219946131

Mã số 3: Python math library

Cập nhật lần cuối vào ngày 19 tháng 8 năm 2022 21:51:50 [UTC/GMT +8 giờ]

Trực quan hóa thực thi mã Python:

Bài Viết Liên Quan

Toplist mới

Bài mới nhất

Chủ Đề