Python sort nested list by second element

Python program to sort a list according to the second element in the sublist.

List is given, our task is to sort a list according to the second element in the sublist. Here we apply simple bubble sort.

Example

Input : [['CCC', 15], ['AAA', 10], ['RRRR', 2],['XXXX', 150]] Output : [['RRRR', 2], ['AAA', 10], ['CCC', 15], ['XXXX', 150]]

Algorithm

Step 1: Given a list. Step 2: We have tried to access the second element of the sublists using the nested loops. Step 3: Traverse through all array elements. Step 4: Last i elements are already in place. Step 5: traverse the array from 0 to n-i-1. Step 6: Swap if the element found is greater than the next element.

Example Code

# Python program to sort the lists using the second element of sublist # In place way to sort, use of third variable. def sortlist[A]: l = len[A] for i in range[0, l]: for j in range[0, l-i-1]: if [A[j][1] > A[j + 1][1]]: tempo = A[j] A[j]= A[j + 1] A[j + 1]= tempo return A # Driver Code A = [['AAA', 10], ['CCC', 15], ['RRRR', 2], ['XXXX', 150]] print[sortlist[A]]

Output

[['RRRR', 2], ['AAA', 10], ['CCC', 15], ['XXXX', 150]]