How many 4 digit numbers can be formed with the digits 3 5 7 8 9 which are greater than 7000?
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How many 4-digit numbers greater than 7000 can be formed by using the digits 3, 5, 7, 8, 9, if repetition is not allowed? Solution not provided. Ans. 72 178 Views A coin is tossed 3 times and the outcomes are recorded. How many possible outcomes are there? Event 1: A coin is tossed and the outcomes recorded. Number of outcomes m = 2Event 2: The coin is tossed again and the outcomes recorded. Number of outcomes n = 2Event 3: The coin is tossed third time and the outcomes recorded. Number of outcomes p = 2∴ By fundamental principle of counting, the total number of outcomes recorded = 548 Views How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that repetition of the digits is not allowed. Number of ways in which place (x) can be filled = 5 m = 5 Number of ways in which place (y) can be filled = 4 (∵ Repetition is not allowed) n = 4 Number of ways in which place (z) can be filled = 3 (∵ Repetition is not allowed) p = 3 ∴ By fundamental principle of counting, the total number of 3 digit numbers formed = m x n x p = 5 x 4 x 3 = 60. 526 Views How many 3-digit odd numbers can be formed from the digits 1,2,3,4,5,6 if: (a) Number of digits available = 6 Number of places [(x), (y) and (z)] for them = 3 Repetition is allowed and the 3-digit numbers formed are odd Number of ways in which box (x) can be filled = 3 (by 1, 3 or 5 as the numbers formed are to be odd) m = 3Number of ways of filling box (y) = 6 (∴ Repetition is allowed) n = 6 Number of ways of filling box (z) = 6 (∵ Repetition is allowed) p = 6∴ Total number of 3-digit odd numbers formed = m x n x p = 3 x 6 x 6 = 108 (b) Number of ways of filling box (x) = 3 (only odd numbers are to be in this box ) m = 3Number of ways of filling box (y) = 5 (∵ Repetition is not allowed) n = 5Number of ways of filling box (z) = 4 (∵ Repetition is not allowed) p = 4∴ Total number of 3-digit odd numbers formed = m x n x p = 3 x 5 x 4 = 60. 231 Views Given 5 flags of different colours, how many different signals can be generated if each signal requires use of 2 flags, one below the other? Number of ways of finding a flag for place 1 = 5 m = 5Number of remaining flags = 4 Number of ways of finding a flag for place 2 to complete the signal = 4 n = 4∴ By fundamental principle of counting, the number of signals generated = 991 Views How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that repetition of the digits is allowed. Number of digits available = 5 Number of places for the digits = 3. Number of ways in which place (x) can be filled = 5 m = 5 Number of ways in which place (y) can be filled = 5 (∵ Repetition is allowed) n = 5 Number of ways in which place (z) can be filled = 5 (∵ Repetition is allowed) p = 5 ∴ By fundamental principle of counting, the number of 3-digit numbers formed. = m x n x p = 5 x 5 x 5 = 125 458 Views How many 4 digits numbers can be formed using digits 1,2 3 5 7 9 repetition not allowed?
How many 4 digit numbers can be formed with repetition?There is 4 possible ways to fill hundredth place as digits cannot be repeated. There is 3 possible ways to fill the first place of four digit number. ∴ 60 four-digit numbers can be formed from the digits 2, 3, 5, 6, 7 and 9. How many 4 digit numbers can be formed using the digits 1 3 4 5 7 9 sum of digits is not allowed?1 Answer. We know that the number of 4 digited numbers that can be formed using the digits 1, 3, 5, 7, 9 is 5P4 = 120. How many 4 digits numbers greater than 7000 can be formed out of the digits?Since you didn't state that digits cannot be repeated, the answer is 4^4 = 256 different numbers. How many four digit numbers can be formed with the digits 3 5 7 8 9 which are Greaterthan 8000 if repetition of digits is not allowed?1 Answer. The required numbers are greater than 8000. Therefore, the thousand's place can be filled with 2 digits: 8 or 9. Thus total number of possible outcomes is 2C1 × 4C1 × 3C1 × 2C1 = 2 × 4 × 3 × 2 = 48. How many 2 digit numbers can be formed with the digits 3 5 6 7 8 if none of the digits is repeated in any of the numbers formed?∴ Required number of numbers = (1 x 5 x 4) = 20. Was this answer helpful? How many 8 digit numbers can be formed with the digits 3/5 and 7?6561 eight-digit numbers can be made from the digits 3, 5 and 7. How many 3 digit numbers can be formed using the digits 1 3 5 7 9 where we are not allowed to repeat the digits?Therefore, a total of 100 3 digit numbers can be formed using the digits 0, 1, 3, 5, 7 when repetition is allowed. How many 41 Answer. The required numbers are greater than 8000. Therefore, the thousand's place can be filled with 2 digits: 8 or 9. Thus total number of possible outcomes is 2C1 × 4C1 × 3C1 × 2C1 = 2 × 4 × 3 × 2 = 48.
How many 4 digits numbers can be formed using digits 1 3 4 5 7 9 repetition not allowed?Hence, there are 720 numbers can be formed.
How many 4 digits numbers greater than 7000 can be formed out of the digits?4000, 4004, 4007, 4009, 4040, 4044, 4047, 4049, 4070, 4074, 4077, 4079, 4090, 4094, 4097, 4099: 16.
How many 4Answer. 120 combinations can be formed.
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