Given a binary number, the task is to write a Python program to convert the given binary number into an equivalent hexadecimal number. i.e convert the number with base value 2 to base value 16. In hexadecimal representation we 16 values to represent a number. Numbers 0-9 are expressed by digits 0-9 and 10-15 are represented by characters from A – F.
Example:
Input: 1111 Output: F Input: 110101 Output: 35 Input: 100001111 Output: 10F
Method 1: User-defined Code To Convert Binary to Hexadecimal
Step 1: Input binary number.
Input: 111101111011
Step 2: Divide your binary number into groups of four, starting from right.
111101111011 = [1111][0111][1011]
Step 3: Convert one 4-digit group of a binary number to one hexadecimal digit.
[1111][0111][1011] = F7B
Below is the Python implementation of the above approach:
Python3
def binToHexa[n]:
bnum = int[n]
temp =
0
mul = 1
count = 1
hexaDeciNum = ['0'] * 100
i = 0
while bnum != 0:
rem = bnum % 10
temp = temp + [rem*mul]
if count % 4 == 0:
if
temp < 10:
hexaDeciNum[i] = chr[temp+48]
else:
hexaDeciNum[i] = chr[temp+55]
mul = 1
temp = 0
count = 1
i = i+1
else:
mul = mul*2
count =
count+1
bnum = int[bnum/10]
if count != 1:
hexaDeciNum[i] = chr[temp+48]
if count == 1:
i = i-1
print["\n Hexadecimal equivalent of {}: ".format[n], end=""]
while i >= 0:
print[end=hexaDeciNum[i]]
i = i-1
if __name__ == '__main__':
binToHexa['1111']
binToHexa['110101']
binToHexa['100001111']
binToHexa['111101111011']
Output:
Hexadecimal equivalent of 1111: F Hexadecimal equivalent of 110101: 35 Hexadecimal equivalent of 100001111: 10F Hexadecimal equivalent of 111101111011: F7B
Method 2: First Convert Binary to Decimal and then Decimal to Hexadecimal
Step 1: Input binary number.
Input: 111101111011 = [111101111011]2
Step 2: Convert binary number to decimal number.
[111101111011]2 = [3963]10
Step 3: Convert the above decimal number to a hexadecimal number.
[3963]10 = [F7B]16
Below is the Python implementation of the above approach:
Python3
def binaryToDecimal[binary]:
binary1 = int[binary]
decimal, i, n = 0, 0, 0
while[binary1 != 0]:
dec =
binary1 % 10
decimal = decimal + dec * pow[2, i]
binary1 = binary1//10
i += 1
return[decimal]
def decToHexa[n]:
hexaDeciNum = ['0'] * 100
i = 0
while[n != 0]:
temp =
0
temp = n % 16
if[temp < 10]:
hexaDeciNum[i] = chr[temp + 48]
i = i + 1
else:
hexaDeciNum[i] = chr[temp + 55]
i = i + 1
n = int[n / 16]
j =
i - 1
while[j >= 0]:
print[[hexaDeciNum[j]], end=""]
j = j - 1
print[]
def binToHexa[n]:
decimal = binaryToDecimal[n]
print["Hexadecimal equivalent of {}: ".format[n]]
decToHexa[decimal]
if __name__ == '__main__':
binToHexa['1111']
binToHexa['110101']
binToHexa['100001111']
binToHexa['111101111011']
Output:
Hexadecimal equivalent of 1111: F Hexadecimal equivalent of 110101: 35 Hexadecimal equivalent of 100001111: 10F Hexadecimal equivalent of 111101111011: F7B
Method 3: Using Predefined Functions
Example 1: Using int[] and hex[]
We use int[] and hex[] to convert a binary number to its equivalent hexadecimal number. Below is the Python implementation using int[] and hex[].
Python3
def binToHexa[n]:
num =
int[n, 2]
hex_num = hex[num]
return[hex_num]
if __name__ == '__main__':
print[binToHexa['1111']]
print[binToHexa['110101']]
print[binToHexa['100001111']]
print[binToHexa['111101111011']]
Output:
0xf 0x35 0x10f 0xf7b
Example 2: Using int[] and format[]
We use int[] and format[] to convert a binary number to its equivalent hexadecimal number. Below is the Python implementation using int[] and format[].
Python3
def binToHexa[n]:
num = int[n, 2]
hex_num = format[num, 'x']
return[hex_num]
if __name__ == '__main__':
print[binToHexa['1111']]
print[binToHexa['110101']]
print[binToHexa['100001111']]
print[binToHexa['111101111011']]
Output:
f 35 10f f7b