Hướng dẫn assert no exception phpunit
PHP 7.4 and PHPUnit 9 Using the PHPUnit homepage example (https://phpunit.de/getting-started/phpunit-9.html):
The homepage also shows us how to test the exception is thrown using the
That's great. But what if I want to test the exception is not thrown given valid input ? Looking at the docs (https://phpunit.readthedocs.io/en/9.3/writing-tests-for-phpunit.html#testing-exceptions) there seems to be no mention of an inverse method to How should I approach this ? EDIT TO ADD: Just to make it perfectly clear, I'm looking to test an asked Sep 1, 2020 at 20:35
Little CodeLittle Code 1,2352 gold badges13 silver badges34 bronze badges 1 If an uncaught or unexpected exception is thrown, the test will fail. You don't have to do anything special, just run the code being tested. If there are no other assertions in the test method, you'll also have to do
answered Sep 1, 2020 at 20:39
Alex HowanskyAlex Howansky 47.6k8 gold badges74 silver badges95 bronze badges 2 Not the answer you're looking for? Browse other questions tagged php phpunit or ask your own question.I’m refactoring a legacy PHP codebase, and that includes writing new tests. While doing that, I found a class method that accepts only a predetermined set of values, and refuses any other value by throwing an exception. Below is a simplified representation of this class:
Promptly, I wrote a test to check if the method was filtering out invalid input values:
Easy peasy. But what if the method is not handling valid
input values correctly? Since the method accepts only a small set of values, we could test all of them. However, PHPUnit 6 doesn’t have a We can easily overcome these limitations by adding an assertion to the end of the test (
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