Hướng dẫn get last directory in path python - lấy thư mục cuối cùng trong python đường dẫn

Trong các dự án hiện tại của tôi, tôi thường chuyển các phần phía sau của một đường dẫn đến một hàm và do đó sử dụng mô -đun ____1010.Để có được phần N-th theo thứ tự ngược lại, tôi đang sử dụng:

from typing import Union
from pathlib import Path

def get_single_subpath_part(base_dir: Union[Path, str], n:int) -> str:
    if n ==0:
        return Path(base_dir).name
    for _ in range(n):
        base_dir = Path(base_dir).parent
    return getattr(base_dir, "name")

path= "/folderA/folderB/folderC/folderD/"

# for getting the last part:
print(get_single_subpath_part(path, 0))
# yields "folderD"

# for the second last
print(get_single_subpath_part(path, 1))
#yields "folderC"

Hơn nữa, để vượt qua phần n-th theo thứ tự ngược của đường dẫn chứa đường dẫn còn lại, tôi sử dụng:

from typing import Union
from pathlib import Path

def get_n_last_subparts_path(base_dir: Union[Path, str], n:int) -> Path:
    return Path(*Path(base_dir).parts[-n-1:])

path= "/folderA/folderB/folderC/folderD/"

# for getting the last part:
print(get_n_last_subparts_path(path, 0))
# yields a `Path` object of "folderD"

# for second last and last part together 
print(get_n_last_subparts_path(path, 1))
# yields a `Path` object of "folderc/folderD"

Lưu ý rằng hàm này trả về

from typing import Union
from pathlib import Path

def get_n_last_subparts_path(base_dir: Union[Path, str], n:int) -> Path:
    return Path(*Path(base_dir).parts[-n-1:])

path= "/folderA/folderB/folderC/folderD/"

# for getting the last part:
print(get_n_last_subparts_path(path, 0))
# yields a `Path` object of "folderD"

# for second last and last part together 
print(get_n_last_subparts_path(path, 1))
# yields a `Path` object of "folderc/folderD"

0Object có thể dễ dàng chuyển đổi thành chuỗi (ví dụ:

from typing import Union
from pathlib import Path

def get_n_last_subparts_path(base_dir: Union[Path, str], n:int) -> Path:
    return Path(*Path(base_dir).parts[-n-1:])

path= "/folderA/folderB/folderC/folderD/"

# for getting the last part:
print(get_n_last_subparts_path(path, 0))
# yields a `Path` object of "folderD"

# for second last and last part together 
print(get_n_last_subparts_path(path, 1))
# yields a `Path` object of "folderc/folderD"

2)

{"id":978,"title":"Python How To Get The Last Directory Name In A Path","advertisement_flag":false,"content":"\n\u003cp\u003eThis short post shows you various ways to get the last directory's name in a path by Python.\u003c/p\u003e\n\n\u003cp\u003eSuppose this is the path you want to extract: \u003cbr\u003e\u003c/p\u003e\n\n\u003cpre\u003e\n\npath =\"/test1/test2/test3/test.txt\"\n\n\u003c/pre\u003e\n\n\u003ch2\u003eMethod 1: os.path.basename\u003c/h2\u003e\n\n\u003cp\u003eos.path.basename: Returns the final component of a pathname \u003cbr\u003e\u003c/p\u003e\n\n\u003cpre\u003e\n\nprint os.path.basename(path) # 'test.txt'\n\nprint os.path.dirname(path) # '/test1/test2/test3'\n\nprint os.path.basename(os.path.dirname(path)) # 'test3'\n\n\u003c/pre\u003e\n\n\u003ch2\u003eMethod 2: os.path.split\u003c/h2\u003e\n\n\u003cp\u003eos.path.split: Return tuple (head, tail) where tail is everything after the final slash.\u003c/p\u003e\n\n\u003cpre\u003e\n\nprint os.path.split(path) #('/test1/test2/test3', 'test.txt')\n\nprint os.path.dirname(path) # '/test1/test2/test3'\n\nprint os.path.split(os.path.dirname(path)) # ('/test1/test2', 'test3')\n\nprint os.path.split(os.path.dirname(path))[1] # 'test3'\n\n\u003c/pre\u003e\n","created_at":"2020-11-13T00:57:05.833Z","author_name":"Bob","tag_groups":["python|Python|false"],"author_id":1,"slug":"python-how-to-get-the-last-directory-name-in-a-path","parent_id":null,"visits":16015,"likes":0,"image":null}

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python

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