Php scandir specific file type

Is there any way to get only images with extensions jpeg, png, gif etc while using

$dir    = '/tmp';
$files1 = scandir($dir);

Madan Sapkota

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asked Jul 12, 2010 at 7:19

You can use glob

$images = glob('/tmp/*.{jpeg,gif,png}', GLOB_BRACE);

If you need this to be case-insensitive, you could use a DirectoryIterator in combination with a RegexIterator or pass the result of scandir to array_map and use a callback that filters any unwanted extensions. Whether you use strpos, fnmatch or pathinfo to get the extension is up to you.

answered Jul 12, 2010 at 7:20

GordonGordon

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4

The actual question was using scandir and the answers end up in glob. There is a huge difference in both where blob considerably heavy. The same filtering can be done with scandir using the following code:

$images = preg_grep('~\.(jpeg|jpg|png)$~', scandir($dir_f));

I hope this would help somebody.

answered Jul 6, 2016 at 13:15

1

Here is a simple way to get only images. Works with PHP >= 5.2 version. The collection of extensions are in lowercase, so making the file extension in loop to lowercase make it case insensitive.

// image extensions
$extensions = array('jpg', 'jpeg', 'png', 'gif', 'bmp');

// init result
$result = array();

// directory to scan
$directory = new DirectoryIterator('/dir/to/scan/');

// iterate
foreach ($directory as $fileinfo) {
    // must be a file
    if ($fileinfo->isFile()) {
        // file extension
        $extension = strtolower(pathinfo($fileinfo->getFilename(), PATHINFO_EXTENSION));
        // check if extension match
        if (in_array($extension, $extensions)) {
            // add to result
            $result[] = $fileinfo->getFilename();
        }
    }
}
// print result
print_r($result);

I hope this is useful if you want case insensitive and image only extensions.

answered Apr 29, 2015 at 15:39

Madan SapkotaMadan Sapkota

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0

I would loop through the files and look at their extensions:

$dir = '/tmp';
$dh  = opendir($dir);
while (false !== ($fileName = readdir($dh))) {
    $ext = substr($fileName, strrpos($fileName, '.') + 1);
    if(in_array($ext, array("jpg","jpeg","png","gif")))
        $files1[] = $fileName;
}
closedir($dh);

answered Jul 12, 2010 at 7:24

JosiahJosiah

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You can search the resulting array afterward and discard files not matching your criteria.

scandir does not have the functionality you seek.

answered Jul 12, 2010 at 7:20

BorealidBorealid

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If you would like to scan a directory and return filenames only you can use this:

$fileNames = array_map(
    function($filePath) {
        return basename($filePath);
    },
    glob('./includes/*.{php}', GLOB_BRACE)
);

scandir() will return . and .. as well as the files, so the above code is cleaner if you just need filenames or you would like to do other things with the actual filepaths

answered Nov 18, 2017 at 17:17

Aaron OlinAaron Olin

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0

I wrote code reusing and putting together parts of the solutions above, in order to make it easier to understand and use:

answered Sep 18, 2021 at 21:39

2