Concatenate 2 numbers in python

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Given two integers a and b. The task is to concatenate these two integers into one integer.

Examples:

Input : a = 806, b = 91
Output : 80691

Input : a = 5, b = 1091
Output : 51091

Method 1: One method of achieving this can be counting the number of digits of second number. Then multiply the first number with 10^digits and adding both the numbers. Below is the implementation.

def numConcat(num1, num2):

     digits = len(str(num2))

     num1 = num1 * (10**digits)

     num1 += num2

     return num1

a = 906

b = 91

print(numConcat(a, b))

Method 2: Another method can be converting both the numbers to the string. Then concatenate them and convert them back to integers. Below is the implementation.

def numConcat(num1, num2):

        num1 = str(num1)

        num2 = str(num2)

        num1 += num2

        return int(num1)

a = 906

b = 91

print(numConcat(a, b))

Output:

90691

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Given two integers n1 and n2, the task is to concatenate these two integers into one integer.
Example: 
 

Input: n1 = 12, n2 = 34
Output: 1234

Input: n1 = 1, n2 = 93
Output: 193

Approach: The simplest approach to do this is: 
 

• Convert both numbers to string
• Concatenate both strings into one, as this is comparatively easy
• Convert this concatenated string back to integer

Program:
 

C++

#include

#include

using namespace std;

int concat(int a, int b)

{

    string s1 = to_string(a);

    string s2 = to_string(b);

    string s = s1 + s2;

    int c = stoi(s);

    return c;

}

int main()

{

    int a = 23;

    int b = 43;

    cout << concat(a, b) << endl;

    return 0;

}

C

#include

#include

#include

int concat(int a, int b)

{

    char s1[20];

    char s2[20];

    sprintf(s1, "%d", a);

    sprintf(s2, "%d", b);

    strcat(s1, s2);

    int c = atoi(s1);

    return c;

}

int main()

{

    int a = 23;

    int b = 43;

    printf("%d\n", concat(a, b));

    return 0;

}

Java

public class GFG {

    static int concat(int a, int b)

    {

        String s1 = Integer.toString(a);

        String s2 = Integer.toString(b);

        String s = s1 + s2;

        int c = Integer.parseInt(s);

        return c;

    }

    public static void main(String args[])

    {

        int a = 23;

        int b = 43;

        System.out.println(concat(a, b));

    }

}

Python3

def concat(a, b):

    s1 = str(a)

    s2 = str(b)

    s = s1 + s2

    c = int(s)

    return c

a = 23

b = 43

print(concat(a, b))

C#

using System;

class GFG

{

    static int concat(int a, int b)

    {

        String s1 = a.ToString();

        String s2 = b.ToString();

        String s = s1 + s2;

        int c = int.Parse(s);

        return c;

    }

    public static void Main(String []args)

    {

        int a = 23;

        int b = 43;

        Console.WriteLine(concat(a, b));

    }

}

Javascript

Output: 

2343

Time Complexity: O(d1+d2) where d1=log10(a) and d2=log10(b)

Auxiliary Space: O(d1+d2)