How to find the factors of 320 in python?

Source Code

# Python Program to find the factors of a number

# This function computes the factor of the argument passed
def print_factors(x):
   print("The factors of",x,"are:")
   for i in range(1, x + 1):
       if x % i == 0:
           print(i)

num = 320

print_factors(num)

Output

The factors of 320 are:
1
2
4
5
8
10
16
20
32
40
64
80
160
320

Note: To find the factors of another number, change the value of num.

In this program, the number whose factor is to be found is stored in num, which is passed to the print_factors() function. This value is assigned to the variable x in print_factors().

In the function, we use the for loop to iterate from i equal to x. If x is perfectly divisible by i, it's a factor of x.

FAQs on Factors of 320

What are Factors of 320?

The factors of 320 are 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 64, 80, 160 and 320

Is 320 a Perfect Square?

No, 320 is not a perfect square, because it cannot be factored as number × number.

What are the Factors of 320 and 350?

  • The factors of 320 are 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 64, 80, 160 and 320
  • The factors of 350 are 1, 2, 5, 7, 10, 14, 25, 35, 50, 70, 175 and 350

What are Prime Factors of 320?

The prime factors of 320 are 2 and 5.

What is the Sum of the Factors of 320?

The factors of 320 are 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 64, 80, 160 and 320. The sum of the factors of 320 = 762.

Here is an example if you want to use the primes number to go a lot faster. These lists are easy to find on the internet. I added comments in the code.

# http://primes.utm.edu/lists/small/10000.txt
# First 10000 primes

_PRIMES = (2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 
        31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 
        73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 
        127, 131, 137, 139, 149, 151, 157, 163, 167, 173, 
        179, 181, 191, 193, 197, 199, 211, 223, 227, 229, 
        233, 239, 241, 251, 257, 263, 269, 271, 277, 281, 
        283, 293, 307, 311, 313, 317, 331, 337, 347, 349, 
        353, 359, 367, 373, 379, 383, 389, 397, 401, 409, 
        419, 421, 431, 433, 439, 443, 449, 457, 461, 463, 
        467, 479, 487, 491, 499, 503, 509, 521, 523, 541, 
        547, 557, 563, 569, 571, 577, 587, 593, 599, 601, 
        607, 613, 617, 619, 631, 641, 643, 647, 653, 659, 
        661, 673, 677, 683, 691, 701, 709, 719, 727, 733, 
        739, 743, 751, 757, 761, 769, 773, 787, 797, 809, 
        811, 821, 823, 827, 829, 839, 853, 857, 859, 863, 
        877, 881, 883, 887, 907, 911, 919, 929, 937, 941, 
        947, 953, 967, 971, 977, 983, 991, 997, 1009, 1013, 
# Mising a lot of primes for the purpose of the example
)


from bisect import bisect_left as _bisect_left
from math import sqrt as _sqrt


def get_factors(n):
    assert isinstance(n, int), "n must be an integer."
    assert n > 0, "n must be greather than zero."
    limit = pow(_PRIMES[-1], 2)
    assert n <= limit, "n is greather then the limit of {0}".format(limit)
    result = set((1, n))
    root = int(_sqrt(n))
    primes = [t for t in get_primes_smaller_than(root + 1) if not n % t]
    result.update(primes)  # Add all the primes factors less or equal to root square
    for t in primes:
        result.update(get_factors(n/t))  # Add all the factors associted for the primes by using the same process
    return sorted(result)


def get_primes_smaller_than(n):
    return _PRIMES[:_bisect_left(_PRIMES, n)]

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Nội dung chính

  • Source Code
  • Source Code: Using Loops
  • Euclidean algorithm
  • Source Code: Using the Euclidean Algorithm
  • How do you calculate the number of common factors in Python?
  • How to find the factors of 320 in Python?
  • What are common divisors in Python?
  • What Python topics should I know to understand this example?
  • How do you find common factors in Python?
  • How do you make a python HCF program?
  • How do you find the common factor of 3 numbers in Python?
  • How do you find the common factors program?

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    Given two integer numbers, the task is to find the count of all common divisors of given numbers?

    Input : a = 12, b = 24
    Output: 6
    Explanation: all common divisors are 1, 2, 3, 4, 6 and 12
    Input : a = 3, b = 17
    Output: 1
    Explanation: all common divisors are 1
    Input : a = 20, b = 36
    Output: 3
    Explanation: all common divisors are 1, 2, 4

    Python

    a = 12

    b = 24

    n = 0

    for i in range(1, min(a, b)+1):

        if a%i==b%i==0:

            n+=1

    print(n)

    Time Complexity: O(min(a, b)), Where a and b is the given number.
    Auxiliary Space: O(1)

    Please refer complete article on Common Divisors of Two Numbers for more details!

    Source Code

    # Python Program to find the factors of a number
    
    # This function computes the factor of the argument passed
    def print_factors(x):
       print("The factors of",x,"are:")
       for i in range(1, x + 1):
           if x % i == 0:
               print(i)
    
    num = 320
    
    print_factors(num)
    

    Output

    The factors of 320 are:
    1
    2
    4
    5
    8
    10
    16
    20
    32
    40
    64
    80
    160
    320
    

    Note: To find the factors of another number, change the value of num.

    In this program, the number whose factor is to be found is stored in num, which is passed to the print_factors() function. This value is assigned to the variable x in print_factors().

    In the function, we use the for loop to iterate from i equal to x. If x is perfectly divisible by i, it's a factor of x.

    In this example, you will learn to find the GCD of two numbers using two different methods: function and loops and, Euclidean algorithm

    To understand this example, you should have the knowledge of the following Python programming topics:

    • Python Functions
    • Python Recursion
    • Python Function Arguments

    The highest common factor (H.C.F) or greatest common divisor (G.C.D) of two numbers is the largest positive integer that perfectly divides the two given numbers. For example, the H.C.F of 12 and 14 is 2.

    Source Code: Using Loops

    # Python program to find H.C.F of two numbers
    
    # define a function
    def compute_hcf(x, y):
    
    # choose the smaller number
        if x > y:
            smaller = y
        else:
            smaller = x
        for i in range(1, smaller+1):
            if((x % i == 0) and (y % i == 0)):
                hcf = i 
        return hcf
    
    num1 = 54 
    num2 = 24
    
    print("The H.C.F. is", compute_hcf(num1, num2))
    

    Output

    The H.C.F. is 6
    

    Here, two integers stored in variables num1 and num2 are passed to the compute_hcf() function. The function computes the H.C.F. these two numbers and returns it.

    In the function, we first determine the smaller of the two numbers since the H.C.F can only be less than or equal to the smallest number. We then use a for loop to go from 1 to that number.

    In each iteration, we check if our number perfectly divides both the input numbers. If so, we store the number as H.C.F. At the completion of the loop, we end up with the largest number that perfectly divides both the numbers.

    The above method is easy to understand and implement but not efficient. A much more efficient method to find the H.C.F. is the Euclidean algorithm.

    Euclidean algorithm

    This algorithm is based on the fact that H.C.F. of two numbers divides their difference as well.

    In this algorithm, we divide the greater by smaller and take the remainder. Now, divide the smaller by this remainder. Repeat until the remainder is 0.

    For example, if we want to find the H.C.F. of 54 and 24, we divide 54 by 24. The remainder is 6. Now, we divide 24 by 6 and the remainder is 0. Hence, 6 is the required H.C.F.

    Source Code: Using the Euclidean Algorithm

    # Function to find HCF the Using Euclidian algorithm
    def compute_hcf(x, y):
       while(y):
           x, y = y, x % y
       return x
    
    hcf = compute_hcf(300, 400)
    print("The HCF is", hcf)

    Here we loop until y becomes zero. The statement x, y = y, x % y does swapping of values in Python. Click here to learn more about swapping variables in Python.

    In each iteration, we place the value of y in x and the remainder (x % y) in y, simultaneously. When y becomes zero, we have H.C.F. in x.

    How do you calculate the number of common factors in Python?

    This can be done efficiently using the Euclidian algorithm, but even better, Python has a built-in function math.gcd for that. Count the number of divisors of g . from math import gcd def num_common_factors (a, b): """ Return the number of common factors of a and b.

    How to find the factors of 320 in Python?

    # Python Program to find the factors of a number # This function computes the factor of the argument passed def print_factors(x): print("The factors of",x,"are:") for i in range(1, x + 1): if x % i == 0: print(i) num = 320 print_factors(num) Output. The factors of 320 are: 1 2 4 5 8 10 16 20 32 40 64 80 160 320

    What are common divisors in Python?

    Common divisors are numbers that divide both the numbers perfectly. Here, we will learn what are common divisors, a method to find the common divisors and a Python program to find the common divisors of two numbers. If you want the implementation of the same using a Python program, you are in the right place.

    What Python topics should I know to understand this example?

    To understand this example, you should have the knowledge of the following Python programming topics: The highest common factor (H.C.F) or greatest common divisor (G.C.D) of two numbers is the largest positive integer that perfectly divides the two given numbers. For example, the H.C.F of 12 and 14 is 2.

    How do you find common factors in Python?

    Method to find common divisors of two numbers.

    Store the two numbers in variable 'num1' and 'num2'..

    Declare a variable say 'i' and initialize it with 1..

    Check the divisibility of both numbers by 'i'..

    If both numbers are divisible, display the common divisor i.e. 'i'..

    Increment the value of 'i' by 1..

    How do you make a python HCF program?

    num1 = int(input("Enter first number: ")) num2 = int(input("Enter second number: ")) # printing the result for the users. print("The H.C.F. of", num1,"and", num2,"is", calculate_hcf(num1, num2))

    How do you find the common factor of 3 numbers in Python?

    Python code:.

    import math..

    n1=int(input(“ENTER THE FIRST NUMBER “)).

    n2=int(input(“ENTER SECOND NUMBER “)).

    n3=int(input(“ENTER THIRD NUMBER “)).

    print(“THE GCD OF GIVEN NUMBERS:”,math.gcd(math.gcd(n1,n2),n3)).

    How do you find the common factors program?

    How to Find the Greatest Common Factor.

    Write all the factors of each number..

    Select the common factors..

    Select the greatest number, as GCF..

    How do you find the factors of 320?

    Factors of 320.
    Factors of 320: 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 64, 80, 160 and 320..
    Factors of -320: -1, -2, -4, -5, -8, -10, -16, -20, -32, -40, -64, -80, -160 and -320..
    Prime Factorization of 320: 26 × 5..

    How do you find the factor of a number in Python?

    Source Code. Note: To find the factors of another number, change the value of num . In this program, the number whose factor is to be found is stored in num , which is passed to the print_factors() function. This value is assigned to the variable x in print_factors() .

    How do you find the factors of a large number in Python?

    The [i, n/i] for i in range(1, int(sqrt(n)) + 1) if n % i == 0 returns a pair of factors if the remainder when you divide n by the smaller one is zero (it doesn't need to check the larger one too; it just gets that by dividing n by the smaller one.)

    How do you find the common factor of 3 numbers in Python?

    Working:.
    Step 1: Import math module..
    Step 2: Read the first number..
    Step 3: Read the second number..
    Step 4: Read the third number..
    Step 5: Print the gcd of three numbers by using in-built gcd function . find gcd of two numbers and then find the gcd of remaing number and gcd of two numbers which gives gcd of three numbers..

    What are the factors of Python?

    Python Programs The number which has only two factors 1 and itself, those numbers are called the prime number. The numbers which have more than two factors are called composite numbers. To find the factor of a positive number “N” divide that number using natural numbers 1 to “N”.