Hướng dẫn how do you count punctuations in python? - làm thế nào để bạn đếm dấu câu trong python?

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Đọcstring.punctuation is a pre-initialized string used as string constant. In Python, string.punctuation will give the all sets of punctuation.

Bàn luận string.punctuation

Trong Python3, string.punctuation là một chuỗi được khởi tạo trước được sử dụng làm hằng số chuỗi. Trong Python, string.punctuation sẽ cung cấp cho tất cả các bộ chấm câu. Doesn’t take any parameter, since it’s not a function.

Cú pháp: String.Punction Return all sets of punctuation.

Tham số: Không lấy bất kỳ tham số nào, vì nó không phải là một hàm.Make sure to import string library function inorder to use string.punctuation

Trả về: Trả về tất cả các bộ chấm câu.

Lưu ý: Đảm bảo nhập chức năng thư viện chuỗi để sử dụng string.punctuation

Mã số 1:

import string
a = "I'm not gonna post my homework as question on OS again, I'm not gonna..."

count = lambda l1, l2: len(list(filter(lambda c: c in l2, l1)))

a_chars =  count(a, string.ascii_letters)
a_punct = count(a, string.punctuation)

import string
a = "I'm not gonna post my homework as question on OS again, I'm not gonna..."

count = lambda l1, l2: len(list(filter(lambda c: c in l2, l1)))

a_chars =  count(a, string.ascii_letters)
a_punct = count(a, string.punctuation)

import string
a = "I'm not gonna post my homework as question on OS again, I'm not gonna..."

count = lambda l1, l2: len(list(filter(lambda c: c in l2, l1)))

a_chars =  count(a, string.ascii_letters)
a_punct = count(a, string.punctuation)

import string
a = "I'm not gonna post my homework as question on OS again, I'm not gonna..."

count = lambda l1, l2: len(list(filter(lambda c: c in l2, l1)))

a_chars =  count(a, string.ascii_letters)
a_punct = count(a, string.punctuation)

!"#$%&'()*+, -./:;<=>?@[\]^_`{|}~

import string
a = "I'm not gonna post my homework as question on OS again, I'm not gonna..."

count = lambda l1, l2: len(list(filter(lambda c: c in l2, l1)))

a_chars =  count(a, string.ascii_letters)
a_punct = count(a, string.punctuation)

import string
a = "I'm not gonna post my homework as question on OS again, I'm not gonna..."

count = lambda l1, l2: len(list(filter(lambda c: c in l2, l1)))

a_chars =  count(a, string.ascii_letters)
a_punct = count(a, string.punctuation)

import string
a = "I'm not gonna post my homework as question on OS again, I'm not gonna..."

count = lambda l1, l2: len(list(filter(lambda c: c in l2, l1)))

a_chars =  count(a, string.ascii_letters)
a_punct = count(a, string.punctuation)

Lưu ý: Đảm bảo nhập chức năng thư viện chuỗi để sử dụng string.punctuation

Mã số 1:

import string
a = "I'm not gonna post my homework as question on OS again, I'm not gonna..."

count = lambda l1, l2: len(list(filter(lambda c: c in l2, l1)))

a_chars =  count(a, string.ascii_letters)
a_punct = count(a, string.punctuation)

import string
a = "I'm not gonna post my homework as question on OS again, I'm not gonna..."

count = lambda l1, l2: len(list(filter(lambda c: c in l2, l1)))

a_chars =  count(a, string.ascii_letters)
a_punct = count(a, string.punctuation)

import string
a = "I'm not gonna post my homework as question on OS again, I'm not gonna..."

count = lambda l1, l2: len(list(filter(lambda c: c in l2, l1)))

a_chars =  count(a, string.ascii_letters)
a_punct = count(a, string.punctuation)

import string
a = "I'm not gonna post my homework as question on OS again, I'm not gonna..."

count = lambda l1, l2: len(list(filter(lambda c: c in l2, l1)))

a_chars =  count(a, string.ascii_letters)
a_punct = count(a, string.punctuation)

import string
a = "I'm not gonna post my homework as question on OS again, I'm not gonna..."

count = lambda l1, l2: len(list(filter(lambda c: c in l2, l1)))

a_chars =  count(a, string.ascii_letters)
a_punct = count(a, string.punctuation)

Đầu ra:

Output:

Punctuation:,
Punctuation: !
Punctuation:,
Punctuation: ?