What is if isset ($_ post submit )) in php?

I have a little problem with my if(isset($_POST['submit'])) code. What I want is some echos and a table to not appear when the script is open but I do want it to show when the submit button for the form has been clicked. The problem is though that when I include the if(isset($_POST['submit'])) function, when I click on the submit button it does not display the echos and the table at all. Why is this and can you help me out with this issue please.

Below is the code:

    








NOTE: If a search box is left blank, then the form will search for all data under that specific field

        
Session ID: 
      
Module Number: 
      
Teacher Username: 
      
Student Username: 
      
Grade: 
      
Order Results By: 
Session ID
Module Number
Teacher Username
Student Username
Grade




Your Search: Session ID: "; if (empty($sessionid))echo "'All Sessions'"; else echo "'$sessionid'";echo ", Module ID: "; if (empty($moduleid))echo "'All Modules'"; else echo "'$moduleid'";echo ", Teacher Username: "; if (empty($teacherid))echo "'All Teachers'"; else echo "'$teacherid'";echo ", Student Username: "; if (empty($studentid))echo "'All Students'"; else echo "'$studentid'";echo ", Grade: "; if (empty($grade))echo "'All Grades'"; else echo "'$grade'"; "
";
echo "
Number of Records Shown in Result of the Search: $num
";
echo "";
while ($row = mysql_fetch_array($result)){
echo "";
echo "";
echo "";
echo "";
echo "";
echo "";
echo "";
echo "";
echo "";
}
echo "


Student Id
Forename
Session Id
Grade
Mark
Module
Teacher
" . $row['StudentId'] . "
" . $row['Forename'] . "
" . $row['SessionId'] . "
" . $row['Grade'] . "
" . $row['Mark'] . "
" . $row['ModuleName'] . "
" . $row['TeacherId'] . "
";
}
mysql_close();
?>

Any help will be much appreciated, Thank You.

Clive

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asked Oct 15, 2011 at 3:07

BruceyBanditBruceyBandit

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You need to give your submit a name or it won't be available using $_POST['submit']:

answered Oct 15, 2011 at 3:12

1

What you're checking

if(isset($_POST['submit']))

but there's no variable name called "submit". well i want you to understand why it doesn't works. lets imagine if you give your submit button name delete and check if(isset($_POST['delete'])) then it works in this code you didn't give any name to submit button and checking its exist or not with isset(); function so php didn't find any variable like "submit" so its not working now try this :

answered Oct 15, 2011 at 8:03

Mohit BumbMohit Bumb

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0

You never named your submit button, so as far as the form is concerned it's just an action.

Either:

1. Name the submit button ()
2. Test if (!empty($_POST)) instead to detect when data has been posted.

Remember that keys in the $_POST superglobal only appear for named input elements. So, unless the element has the name attribute, it won't come through to $_POST (or $_GET/$_REQUEST)

answered Oct 15, 2011 at 3:11

Brad ChristieBrad Christie

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1

Whats wrong in this?

login.php

if(isset($_POST['submit']) && !empty($_POST['submit'])) {
  // if (!logged_in()) 
  echo 'asodj';
}

Jeff Miller

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answered Mar 15, 2017 at 18:18

You must give a name to your submit button

Then you can call the button with $_POST['login']

Aleksandr M

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answered Mar 16, 2015 at 10:51

The $_post function need the name value like:

Call

$var = strip_tags($_POST['example']);
if (isset($var)){
    // your code here
}

Laurel

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answered Sep 27, 2016 at 22:03

Another option is to use

$_SERVER['REQUEST_METHOD'] == 'POST'

answered Oct 19, 2018 at 22:21

1

If (isset($_POST[submit]) ,any time try this function it displays error code (do not access super global $_POST array directly)

answered Aug 4, 2021 at 19:50

You can use :

"

Or if you will to us buttons

Submit

In your php script if(isset($_POST['submit']))

The most important is the "name" attribute to perform the submission of the form

answered Apr 21 at 12:01

What is isset ($_ POST in PHP?

What does Isset POST do?

Does isset () function do in PHP?

How do you check if a submit button is clicked in PHP?