How can i get month in php?

I want to be able to figure out the month of the current date variable. I'm ex vb.net and the way to do it there is just date.Month. How do I do this in PHP?

Thanks,

Jonesy

I used date_format($date, "m"); //01, 02..12

This is what I wanted, question now is how do I compare this to an int since $monthnumber = 01 just becomes 1

John

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asked Sep 22, 2010 at 9:51

iamjonesyiamjonesy

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2

See http://php.net/date

date('m') or date('n') or date('F') ...

Update

m Numeric representation of a month, with leading zeros 01 through 12

n Numeric representation of a month, without leading zeros 1 through 12

F Alphabetic representation of a month January through December

....see the docs link for even more options.

answered Sep 22, 2010 at 9:54

What does your "data variable" look like? If it's like this:

$mydate = "2010-05-12 13:57:01";

You can simply do:

$month = date("m",strtotime($mydate));

For more information, take a look at date and strtotime.

EDIT:

To compare with an int, just do a date_format($date,"n"); which will give you the month without leading zero.

Alternatively, try one of these:

if((int)$month == 1)...
if(abs($month) == 1)...

Or something weird using ltrim, round, floor... but date_format() with "n" would be the best.

Kwido

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answered Sep 22, 2010 at 9:56

oezioezi

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$unixtime = strtotime($test);
echo date('m', $unixtime); //month
echo date('d', $unixtime); 
echo date('y', $unixtime );

answered Sep 22, 2010 at 9:56

Pramendra GuptaPramendra Gupta

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as date_format uses the same format as date ( http://www.php.net/manual/en/function.date.php ) the "Numeric representation of a month, without leading zeros" is a lowercase n .. so

echo date('n'); // "9"

answered Sep 22, 2010 at 10:45

HannesHannes

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As it's not specified if you mean the system's current date or the date held in a variable, I'll answer for latter with an example.

answered Apr 7, 2018 at 4:59

J-a-n-u-sJ-a-n-u-s

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1

To compare with an int do this:

answered Feb 29, 2020 at 16:20

e102e102

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