How do you convert a number to 8 bit binary in python?

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Given a decimal number as input, the task is to write a Python program to convert the given decimal number into an equivalent binary number.
Examples : 

Input : 7                                                         
Output :111

Input :10
Output :1010

Method #1: Recursive solution

DecimalToBinary(num):
        if num >= 1:
            DecimalToBinary(num // 2)
           print num % 2 

Below is the implementation of the above recursive solution: 

Python3

def DecimalToBinary(num):

    if num >= 1:

        DecimalToBinary(num // 2)

    print(num % 2, end = '')

if __name__ == '__main__':

    dec_val = 24

    DecimalToBinary(dec_val)

Method #2: Decimal to binary using in-built function 

Python3

def decimalToBinary(n):

    return bin(n).replace("0b", "")

if __name__ == '__main__':

    print(decimalToBinary(8))

    print(decimalToBinary(18))

    print(decimalToBinary(7))

Method #3:Without in-built function

Python3

def decimalToBinary(n):

    return "{0:b}".format(int(n))

if __name__ == '__main__':

    print(decimalToBinary(8))

    print(decimalToBinary(18))

    print(decimalToBinary(7))

Quick Ninja Method: One Line Code to Convert Decimal to Binary with user input

Python3

or 

Python3

decNum = 4785

print(bin(decNum)[2:])

decNum1 = 10

print(bin(decNum1)[2:])

decNum2 = 345

print(bin(decNum2)[2:])

Output

1001010110001
1010
101011001