Hướng dẫn php echo image size

Nigel Ren

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asked Jun 12, 2018 at 6:13

4

You can use getimagesize() function http://php.net/manual/en/function.getimagesize.php to fetch image size

";

    for ($row=1; $row <= 4; $row++) {
        echo "

Bhumi ShahBhumi Shah

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I am echoing an image which works fine, but then i want to set how big it needs to be, and I just can't seem to get the syntax right.

This is what I have:

echo "
cyborg86pl
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 asked Apr 22, 2014 at 15:43
 
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You are mixing single and double quotes. So you get a syntax error.
This works:



echo " ';
 answered Apr 22, 2014 at
15:46
 
theHackertheHacker
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try changing double quotes into single quotes for these attributes
height='130' width='150'
since double quotes are actually delimiting
the PHP string. Optionally you may instead escape the double quotes like so
height=\"130\" width=\"150\"
but this syntax is less readable and more error prone (not recommended)
 answered Apr 22, 2014 at 15:45
 
Fabrizio CalderanFabrizio Calderan
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ok its here
echo '';
 answered Apr 22, 2014 at 15:45
 
4
You can uses variables inside double quotes, like this:
Pedro LobitoPedro Lobito
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Sometimes the way that you're using causes to errors if you don't do it properly.Therefore you can try this way also.

if you're using this inside a loop,you can do like this.



Hope this helped to you.
 answered Apr 22, 2014 at 15:52
 
CodeCanyonCodeCanyon
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