Python random 0 or 1

The problem is that your code generates a single value and then prints it repeatedly. A simplified version of the problem would be this:

k = random.randint(0, 1) # decide on k once
for _ in range(n):
    print(k) # print k over and over again

This will generate k, then print it n times, but what you want is to generate a new value to print each time

for _ in range(n):
    k = random.randint(0, 1) # decide on a k each time the loop runs
    print(k)

You can generate the matrix itself using a nested list comprehension (which may be more than you want to know at this point, but worth showing)

[[random.randint(0, 1) for _ in range(n)] for _ in range(n)]

the inner part [random.randint(0, 1) for _ in range(n)] will give you n values in the range 0-1. nesting that in another comprehension gives you n of those.

Python has a random module that provides different functions to generate or manipulate random numbers. The random number generator functions are used in real-time applications like lotteries, lucky draws, or games.

To get a random number between 0 and 1 in Python, use the random.uniform() method. The random.uniform() method accepts two numbers and returns the random floating number between them.

Syntax

random.uniform(x, y)

Arguments

x: It is a required parameter. It is a number specifying the lowest possible outcome.

y: It is a required parameter. It is a number identifying the highest possible outcome.

Example

Use the random.uniform() method to get the floating random number between 0 and 1.

import random

print(random.uniform(0, 1))

Output

0.19400286710553283

As you can see that the output floating number is between 0 and 1. It returns a random floating-point number N such that x <= N <= y for x <= y and y <= N <= x for y < x.

To generate a random float with N digits to the right of the point, use the round() function and pass the second argument of the round() function as several decimals.

import random

print(round(random.uniform(0, 1), 2))

Output

0.77

We got the output with 2 decimal points because we passed 2 as a second argument to the round() function.

Generate numbers between 0 and 1 using random.random()

The Random random() method generates the number between 0.0 and 1.0. The random.random() method does not accept any parameter.

Syntax

random.random()

Arguments

The random() method does not accept any argument.

Example

Generate a random floating number using random.random() method.

import random

print(random.random())

Output

0.7167279190081859

Every time you rerun the code, it will return a different output.

import random

print(random.random())

Output

0.462870643862876

But you can see that it always returns the random floating number between 0 and 1.

Generate a range between 0 and 1

To generate a range of 10 numbers between 0 and 1, you can use the for loop and range() method.

import random

for i in range(10):
    print(random.random())

Output

0.37193858005932523
0.5951347699073494
0.751762108984189
0.34839832842976537
0.6955311460839113
0.5327516816125327
0.6193354493744598
0.6677134225025977
0.7075320672349881
0.12548018574953634

Python random.randrange() Method

The randrange() is a built-in Python method that returns a randomly selected element from the specified range. Here, we can pass the range from 0 to 1. But it will not return the floating value. So it will return 0 every time you run the function.

import random

print(random.randrange(0, 1))

Output

python3 app.py
0
python3 app.py
0
python3 app.py
0
python3 app.py
0

You can see from the output that it always returns 0.

That is it for this tutorial.

Related posts

Python random seed()

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Python random sample()

How do you generate a random integer 0 or 1 in Python?

Does random random include 0 and 1?

Does Python random include 1?

Can random random () give 1?