How do i count the number of strings in php?

(PHP 4, PHP 5, PHP 7, PHP 8)

substr_count — Count the number of substring occurrences

Description

substr_count(
    string $haystack,
    string $needle,
    int $offset = 0,
    ?int $length = null
): int

Note:

This function doesn't count overlapped substrings. See the example below!

Parameters

The string to search in

The substring to search for

The offset where to start counting. If the offset is negative, counting starts from the end of the string.

The maximum length after the specified offset to search for the substring. It outputs a warning if the offset plus the length is greater than the haystack length. A negative length counts from the end of haystack.

Return Values

This function returns an int.

Changelog

Examples

Example #1 A substr_count() example

$text = 'This is a test';
echo strlen($text); // 14echo substr_count($text, 'is'); // 2

// the string is reduced to 's is a test', so it prints 1

See Also

• count_chars() - Return information about characters used in a string
• strpos() - Find the position of the first occurrence of a substring in a string
• substr() - Return part of a string
• strstr() - Find the first occurrence of a string

tuxedobob ¶

6 years ago

It's worth noting this function is surprisingly fast. I first ran it against a ~500KB string on our web server. It found 6 occurrences of the needle I was looking for in 0.0000 seconds. Yes, it ran faster than microtime() could measure.

Looking to give it a challenge, I then ran it on a Mac laptop from 2010 against a 120.5MB string. For one test needle, it found 2385 occurrences in 0.0266 seconds. Another test needs found 290 occurrences in 0.114 seconds.

Long story short, if you're wondering whether this function is slowing down your script, the answer is probably not.

flobi at flobi dot com ¶

15 years ago

Making this case insensitive is easy for anyone who needs this.  Simply convert the haystack and the needle to the same case (upper or lower).

substr_count(strtoupper($haystack), strtoupper($needle))

tweston at bangordailynews dot com ¶

7 years ago

To account for the case that jrhodes has pointed out, we can change the line to:

substr_count ( implode( ',', $haystackArray ), $needle );

This way:

array (
  0 => "mystringth",
  1 => "atislong"
);

Becomes

mystringth,atislong

Which brings the count for $needle = "that" to 0 again.

jrhodes at roket-enterprises dot com ¶

13 years ago

It was suggested to use

substr_count ( implode( $haystackArray ), $needle );

instead of the function described previously, however this has one flaw.  For example this array:

array (
  0 => "mystringth",
  1 => "atislong"
);

If you are counting "that", the implode version will return 1, but the function previously described will return 0.

XinfoX X at X XkarlX X-X XphilippX X dot X XdeX ¶

18 years ago

Yet another reference to the "cgcgcgcgcgcgc" example posted by "chris at pecoraro dot net":

Your request can be fulfilled with the Perl compatible regular expressions and their lookahead and lookbehind features.

The example

$number_of_full_pattern = preg_match_all('/(cgc)/', "cgcgcgcgcgcgcg", $chunks);

works like the substr_count function. The variable $number_of_full_pattern has the value 3, because the default behavior of Perl compatible regular expressions is to consume the characters of the string subject that were matched by the (sub)pattern. That is, the pointer will be moved to the end of the matched substring.
But we can use the lookahead feature that disables the moving of the pointer:

$number_of_full_pattern = preg_match_all('/(cg(?=c))/', "cgcgcgcgcgcgcg", $chunks);

In this case the variable $number_of_full_pattern has the value 6.
Firstly a string "cg" will be matched and the pointer will be moved to the end of this string. Then the regular expression looks ahead whether a 'c' can be matched. Despite of the occurence of the character 'c' the pointer is not moved.

info at fat-fish dot co dot il ¶

15 years ago

a simple version for an array needle (multiply sub-strings):
function substr_count_array( $haystack, $needle ) {
     $count = 0;
     foreach ($needle as $substring) {
          $count += substr_count( $haystack, $substring);
     }
     return $count;
}
?>

php at blink dot at ¶

8 years ago

This will handle a string where it is unknown if comma or period are used as thousand or decimal separator. Only exception where this leads to a conflict is when there is only a single comma or period and 3 possible decimals (123.456 or 123,456). An optional parameter is passed to handle this case (assume thousands, assume decimal, decimal when period, decimal when comma). It assumes an input string in any of the formats listed below.

function toFloat($pString, $seperatorOnConflict="f")
{
    $decSeperator=".";
    $thSeperator="";

    $pString=str_replace(" ", $thSeperator, $pString);

    $firstPeriod=strpos($pString, ".");
    $firstComma=strpos($pString, ",");
    if($firstPeriod!==FALSE && $firstComma!==FALSE) {
        if($firstPeriod<$firstComma) {
            $pString=str_replace(".", $thSeperator, $pString);
            $pString=str_replace(",", $decSeperator, $pString);
        }
        else {
            $pString=str_replace(",", $thSeperator, $pString);
        }
    }
    else if($firstPeriod!==FALSE || $firstComma!==FALSE) {
        $seperator=$firstPeriod!==FALSE?".":",";
        if(substr_count($pString, $seperator)==1) {
            $lastPeriodOrComma=strpos($pString, $seperator);
            if($lastPeriodOrComma==(strlen($pString)-4) && ($seperatorOnConflict!=$seperator && $seperatorOnConflict!="f")) {
                $pString=str_replace($seperator, $thSeperator, $pString);
            }
            else {
                $pString=str_replace($seperator, $decSeperator, $pString);
            }
        }
        else {
            $pString=str_replace($seperator, $thSeperator, $pString);
        }
    }
    return(float)$pString;
}

function testFloatParsing() {
    $floatvals = array(
        "22 000",
        "22,000",
        "22.000",
        "123 456",
        "123,456",
        "123.456",
        "22 000,76",
        "22.000,76",
        "22,000.76",
        "22000.76",
        "22000,76",
        "1.022.000,76",
        "1,022,000.76",
        "1,000,000",
        "1.000.000",
        "1022000.76",
        "1022000,76",
        "1022000",
        "0.76",
        "0,76",
        "0.00",
        "0,00",
        "1.00",
        "1,00",
        "-22 000,76",
        "-22.000,76",
        "-22,000.76",
        "-22 000",
        "-22,000",
        "-22.000",
        "-22000.76",
        "-22000,76",
        "-1.022.000,76",
        "-1,022,000.76",
        "-1,000,000",
        "-1.000.000",
        "-1022000.76",
        "-1022000,76",
        "-1022000",
        "-0.76",
        "-0,76",
        "-0.00",
        "-0,00",
        "-1.00",
        "-1,00"
    );

        echo "

            foreach ($floatvals as $fval) {
        echo "

                echo "

qeremy [atta] gmail [dotta] com ¶

9 years ago

Unicode example with "case-sensitive" option;

function substr_count_unicode($str, $substr, $caseSensitive = true, $offset = 0, $length = null) {
    if ($offset) {
        $str = substr_unicode($str, $offset, $length);
    }$pattern = $caseSensitive
        ? '~(?:'. preg_quote($substr) .')~u'
        : '~(?:'. preg_quote($substr) .')~ui';
    preg_match_all($pattern, $str, $matches);

    return isset(

gigi at phpmycoder dot com ¶

13 years ago

below was suggested a function for substr_count'ing an array, yet for a simpler procedure, use the following:

substr_count ( implode( $haystackArray ), $needle );
?>