How check value is decimal or not in php?

I need to check in PHP if user entered a decimal number (US way, with decimal point: X.XXX)

Any reliable way to do this?

Uwe Keim

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asked Jul 21, 2011 at 7:22

CodeVirtuosoCodeVirtuoso

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6

You can get most of what you want from is_float, but if you really need to know whether it has a decimal in it, your function above isn't terribly far (albeit the wrong language):

function is_decimal( $val )
{
    return is_numeric( $val ) && floor( $val ) != $val;
}

answered Jul 21, 2011 at 7:28

cwallenpoolecwallenpoole

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7

if you want "10.00" to return true check Night Owl's answer

If you want to know if the decimals has a value you can use this answer.

Works with all kind of types (int, float, string)

if(fmod($val, 1) !== 0.00){
    // your code if its decimals has a value
} else {
    // your code if the decimals are .00, or is an integer
}

Examples:

(fmod(1.00,    1) !== 0.00)    // returns false
(fmod(2,       1) !== 0.00)    // returns false
(fmod(3.01,    1) !== 0.00)    // returns true
(fmod(4.33333, 1) !== 0.00)    // returns true
(fmod(5.00000, 1) !== 0.00)    // returns false
(fmod('6.50',  1) !== 0.00)    // returns true

Explanation:

fmod returns the floating point remainder (modulo) of the division of the arguments, (hence the (!== 0.00))

Modulus operator - why not use the modulus operator? E.g. ($val % 1 != 0)

From the PHP docs:

Operands of modulus are converted to integers (by stripping the decimal part) before processing.

Which will effectively destroys the op purpose, in other languages like javascript you can use the modulus operator

answered Nov 6, 2014 at 13:23

1

If all you need to know is whether a decimal point exists in a variable then this will get the job done...

function containsDecimal( $value ) {
    if ( strpos( $value, "." ) !== false ) {
        return true;
    }
    return false;
}

This isn't a very elegant solution but it works with strings and floats.

Make sure to use !== and not != in the strpos test or you will get incorrect results.

answered Jan 24, 2012 at 4:07

Night OwlNight Owl

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1

another way to solve this: preg_match('/^\d+\.\d+$/',$number); :)

answered Jul 21, 2011 at 7:33

k102k102

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0

The function you posted is just not PHP.

Have a look at is_float [docs].

Edit: I missed the "user entered value" part. In this case you can actually use a regular expression:

^\d+\.\d+$

answered Jul 21, 2011 at 7:26

Felix KlingFelix Kling

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2

I was passed a string, and wanted to know if it was a decimal or not. I ended up with this:

function isDecimal($value) 
{
     return ((float) $value !== floor($value));
}

I ran a bunch of test including decimals and non-decimals on both sides of zero, and it seemed to work.

gen_Eric

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answered Oct 13, 2011 at 16:58

Jeff VJeff V

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1

is_numeric returns true for decimals and integers. So if your user lazily enters 1 instead of 1.00 it will still return true:

echo is_numeric(1); // true
echo is_numeric(1.00); // true

You may wish to convert the integer to a decimal with PHP, or let your database do it for you.

answered Nov 20, 2013 at 14:15

rybo111rybo111

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1

This is a more tolerate way to handle this with user input. This regex will match both "100" or "100.1" but doesn't allow for negative numbers.

/^(\d+)(\.\d+)?$/

answered Sep 10, 2013 at 18:05

ChaoixChaoix

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   // if numeric 

if (is_numeric($field)) {
        $whole = floor($field);
        $fraction = $field - $whole;

        // if decimal            
        if ($fraction > 0)
            // do sth
        else
        // if integer
            // do sth 
}
else

   // if non-numeric
   // do sth

answered Jul 31, 2014 at 12:46

Van BienVan Bien

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i use this:

function is_decimal ($price){
  $value= trim($price); // trim space keys
  $value= is_numeric($value); // validate numeric and numeric string, e.g., 12.00, 1e00, 123; but not -123
  $value= preg_match('/^\d$/', $value); // only allow any digit e.g., 0,1,2,3,4,5,6,7,8,9. This will eliminate the numeric string, e.g., 1e00
  $value= round($value, 2); // to a specified number of decimal places.e.g., 1.12345=> 1.12

  return $value;
}

answered Jul 5, 2014 at 4:19

0

$lat = '-25.3654';

if(preg_match('/./',$lat)) {
    echo "\nYes its a decimal value\n";
}
else{
    echo 'No its not a decimal value';
}

answered Mar 3, 2014 at 11:20

NeocortexNeocortex

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A total cludge.. but hey it works !

$numpart = explode(".", $sumnum); 

if ((exists($numpart[1]) && ($numpart[1] > 0 )){
//    it's a decimal that is greater than zero
} else {
// its not a decimal, or the decimal is zero
}

answered Mar 6, 2015 at 22:22

Duane LortieDuane Lortie

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the easy way to find either posted value is integer and float so this will help you

$postedValue = $this->input->post('value');
if(is_numeric( $postedValue ) && floor( $postedValue ))
{
    echo 'success';
}
else
{
   echo 'unsuccess';
}

if you give 10 or 10.5 or 10.0 the result will be success if you define any character or specail character without dot it will give unsuccess

answered Dec 25, 2019 at 11:57

abubakkar tahirabubakkar tahir

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How about (int)$value != $value? If true it's decimal, if false it's not.

answered Nov 29, 2021 at 15:49

I can't comment, but I have this interesting behaviour. (tested on v. 7.3.19 on a website for php testing online)

If you multiply 50 by 1.1 fmod gives different results than expected. If you do by 1.2 or 1.3 it's fine, if you do another number (like 60 or 40) is also fine.

$price = 50;
$price = $price * 1.1; 

if(strpos($price,".") !== false){
    echo "decimal";
}else{
    echo "not a decimal";
}

echo '
';

if(fmod($price, 1) !== 0.00){
    //echo fmod($price, 1);
    echo "decimal";
} else {
    echo "not a decimal";
}//end if

answered Feb 6 at 18:37

1

Simplest solution is

if(is_float(2.3)){

 echo 'true';

}

answered Aug 24, 2017 at 10:06

Ayyaz ZafarAyyaz Zafar

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If you are working with form validation. Then in this case form send string. I used following code to check either form input is a decimal number or not. I hope this will work for you too.

function is_decimal($input = '') {

    $alphabets = str_split($input);
    $find = array('0','1','2','3','4','5','6','7','8','9','.'); // Please note: All intiger numbers are decimal. If you want to check numbers without point "." then you can remove '.' from array. 

    foreach ($alphabets as $key => $alphabet) {
        if (!in_array($alphabet, $find)) {
            return false;
        }
    }

    // Check if user has enter "." point more then once.
    if (substr_count($input, ".") > 1) {
        return false;
    }

    return true;
}

answered Dec 15, 2017 at 2:17

Adnan AhmadAdnan Ahmad

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function is_decimal_value( $a ) {
    $d=0; $i=0;
    $b= str_split(trim($a.""));
    foreach ( $b as $c ) {
        if ( $i==0 && strpos($c,"-") ) continue;
        $i++;
        if ( is_numeric($c) ) continue;
        if ( stripos($c,".") === 0 ) {
            $d++;
            if ( $d > 1 ) return FALSE;
            else continue;
        } else
        return FALSE;
    }
    return TRUE;
}

Known Issues with the above function:

1) Does not support "scientific notation" (1.23E-123), fiscal (leading $ or other) or "Trailing f" (C++ style floats) or "trailing currency" (USD, GBP etc)

2) False positive on string filenames that match a decimal: Please note that for example "10.0" as a filename cannot be distinguished from the decimal, so if you are attempting to detect a type from a string alone, and a filename matches a decimal name and has no path included, it will be impossible to discern.

answered Feb 10, 2020 at 19:24

Maybe try looking into this as well

!is_int()

answered Dec 23, 2012 at 4:13

Cam TullosCam Tullos

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0

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